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A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armature
Correct answer is between '0.6,0.7'. Can you explain this answer?
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Verified Answer
A 4 pole dc generator has 1200 armature conductors and generates 250 V...
Pole pitch = distance between two adjacent poles
Area of pole face = pole arc times the axial length
Area of pole face = pole arc times the axial length
Most Upvoted Answer
A 4 pole dc generator has 1200 armature conductors and generates 250 V...
Given data:
- Number of poles (p) = 4
- Armature conductors (N) = 1200
- Generated voltage (E) = 250 V
- Speed (N) = 500 rpm
- Pole shoe circle diameter (D) = 0.35 m
- Pole arc to pole pitch ratio (m) = 0.7
- Pole shoe length (l) = 0.2 m
To find: Mean flux density in the air gap (B)
Formula used:
- Generated voltage (E) = 4.44 * f * N * B * A
where f = frequency, N = number of armature conductors, B = flux density, and A = area of air gap
- Pole arc (α) = m * pole pitch (τ)
- Pole pitch (τ) = π * D / p
- Area of air gap (A) = τ * l
Calculation:
- Frequency (f) = N / 2p * N
= 500 / 2 * 4 * 1200
= 10 Hz
- Pole pitch (τ) = π * D / p
= π * 0.35 / 4
= 0.2749 m
- Pole arc (α) = m * pole pitch (τ)
= 0.7 * 0.2749
= 0.1924 m
- Area of air gap (A) = τ * l
= 0.2749 * 0.2
= 0.05498 m²
- Generated voltage (E) = 250 V
- Number of armature conductors (N) = 1200
- Substituting the above values in the formula, we get
B = E / 4.44 * f * N * A
= 250 / 4.44 * 10 * 1200 * 0.05498
= 0.644 T (approximately)
Therefore, the mean flux density in the air gap is 0.644 T (approximately), which is between 0.6 and 0.7 T as given in the answer.
- Number of poles (p) = 4
- Armature conductors (N) = 1200
- Generated voltage (E) = 250 V
- Speed (N) = 500 rpm
- Pole shoe circle diameter (D) = 0.35 m
- Pole arc to pole pitch ratio (m) = 0.7
- Pole shoe length (l) = 0.2 m
To find: Mean flux density in the air gap (B)
Formula used:
- Generated voltage (E) = 4.44 * f * N * B * A
where f = frequency, N = number of armature conductors, B = flux density, and A = area of air gap
- Pole arc (α) = m * pole pitch (τ)
- Pole pitch (τ) = π * D / p
- Area of air gap (A) = τ * l
Calculation:
- Frequency (f) = N / 2p * N
= 500 / 2 * 4 * 1200
= 10 Hz
- Pole pitch (τ) = π * D / p
= π * 0.35 / 4
= 0.2749 m
- Pole arc (α) = m * pole pitch (τ)
= 0.7 * 0.2749
= 0.1924 m
- Area of air gap (A) = τ * l
= 0.2749 * 0.2
= 0.05498 m²
- Generated voltage (E) = 250 V
- Number of armature conductors (N) = 1200
- Substituting the above values in the formula, we get
B = E / 4.44 * f * N * A
= 250 / 4.44 * 10 * 1200 * 0.05498
= 0.644 T (approximately)
Therefore, the mean flux density in the air gap is 0.644 T (approximately), which is between 0.6 and 0.7 T as given in the answer.
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A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer?
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A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer?.
A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer?.
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A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer?, a detailed solution for A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer? has been provided alongside types of A 4 pole dc generator has 1200 armature conductors and generates 250 V on open circuit running at a speed of 500 rpm. The diameter of the pole shoe circle is 0.35 m and the ration of pole arc to pole pitch is 0.7 while the length of the shoe is 0.2 m. Find the mean flux density in Tesla in the air gap. Assume lap winding in armatureCorrect answer is between '0.6,0.7'. Can you explain this answer? theory, EduRev gives you an
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