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An auto transformer is used to connect a 12.6 kV distribution line to a 13.8 kV distribution line. It must be capable of handling 2000 kVA. There are three phases, connected Y-Y with their neutrals solidly grounded. What must the NC/NSE­ turn ratio be to accomplish this connection? (NC→ common turn, NSE → Series turn)
    Correct answer is between '10,11'. Can you explain this answer?
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    An auto transformer is used to connect a 12.6 kV distribution line to ...
    The transformer is connected y-y so the primary and secondary phase voltage are the line voltage divided by 3–√3. The turn ratio of each auto transformer is given by
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    An auto transformer is used to connect a 12.6 kV distribution line to ...
    The NC/NSE (Neutral Current to Neutral Source Equivalent) is a parameter used to determine the amount of current flowing through the neutral conductor in an auto transformer. It is calculated using the formula:

    NC/NSE = kVA / (√3 * V)

    Where:
    - NC/NSE is the Neutral Current to Neutral Source Equivalent
    - kVA is the power rating of the auto transformer (2000 kVA)
    - √3 is the square root of 3 (approximately 1.732)
    - V is the line-to-line voltage (12.6 kV or 13.8 kV)

    Let's calculate the NC/NSE for both cases:

    For a 12.6 kV distribution line:
    NC/NSE = 2000 kVA / (1.732 * 12.6 kV) = 77.60 A

    For a 13.8 kV distribution line:
    NC/NSE = 2000 kVA / (1.732 * 13.8 kV) = 72.62 A

    Therefore, the NC/NSE for the 12.6 kV distribution line is 77.60 A, and the NC/NSE for the 13.8 kV distribution line is 72.62 A.
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    An auto transformer is used to connect a 12.6 kV distribution line to a 13.8 kV distribution line. It must be capable of handling 2000 kVA. There are three phases, connected Y-Y with their neutrals solidly grounded. What must the NC/NSE­turn ratio be to accomplish this connection? (NC→ common turn, NSE→ Series turn)Correct answer is between '10,11'. Can you explain this answer?
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    An auto transformer is used to connect a 12.6 kV distribution line to a 13.8 kV distribution line. It must be capable of handling 2000 kVA. There are three phases, connected Y-Y with their neutrals solidly grounded. What must the NC/NSE­turn ratio be to accomplish this connection? (NC→ common turn, NSE→ Series turn)Correct answer is between '10,11'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An auto transformer is used to connect a 12.6 kV distribution line to a 13.8 kV distribution line. It must be capable of handling 2000 kVA. There are three phases, connected Y-Y with their neutrals solidly grounded. What must the NC/NSE­turn ratio be to accomplish this connection? (NC→ common turn, NSE→ Series turn)Correct answer is between '10,11'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An auto transformer is used to connect a 12.6 kV distribution line to a 13.8 kV distribution line. It must be capable of handling 2000 kVA. There are three phases, connected Y-Y with their neutrals solidly grounded. What must the NC/NSE­turn ratio be to accomplish this connection? (NC→ common turn, NSE→ Series turn)Correct answer is between '10,11'. Can you explain this answer?.
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