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For the transistor circuit shown below:
If V1 = 1V and V2 = -12V R1 = 15k and R2 = 100k R= 2.2 k Vcc = 12V Then the Region of operation of transistor is 
  • a)
    Active
  • b)
    Saturation
  • c)
    Cut off
  • d)
    Reverse Active
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
For the transistor circuit shown below:If V1= 1V and V2= -12V R1= 15k ...
V1 = 1V
V2 = -12V
R1 = 15 k
R2 = 100 k
= -0.7V
VBB­ < 0, the Base emitter Junction is reversed biased
Hence Transistor is in cut off mode
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For the transistor circuit shown below:If V1= 1V and V2= -12V R1= 15k and R2= 100k Rc= 2.2 k Vcc= 12V Then the Region of operation of transistor isa)Activeb)Saturationc)Cut offd)Reverse ActiveCorrect answer is option 'C'. Can you explain this answer?
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