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In class 7 maths book on pg no 19 and 20 ( ch 1 integers) there is an example 3 verify (-30)×[13 (-3)]=[(-30)×13] [(-30)×(-3)] Can anyone tell me that how it has solved? Plzz?
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In class 7 maths book on pg no 19 and 20 ( ch 1 integers) there is an ...
Verification of (-30)×[13(-3)]=[(-30)×13][(-30)×(-3)]

Step 1: Write the given expression on both sides of the equation.

LHS: (-30)×[13(-3)]

RHS: [(-30)×13][(-30)×(-3)]

Step 2: Simplify the terms inside the bracket.

LHS: (-30)×[13(-3)] = (-30)×(-39) = 1170

RHS: [(-30)×13][(-30)×(-3)] = (-390)×(90) = 1170

Step 3: Compare both the sides.

LHS: (-30)×[13(-3)] = 1170

RHS: [(-30)×13][(-30)×(-3)] = 1170

Conclusion: Both sides of the equation are equal. Hence, the given expression is verified.

Therefore, (-30)×[13(-3)]=[(-30)×13][(-30)×(-3)] is verified.
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In class 7 maths book on pg no 19 and 20 ( ch 1 integers) there is an ...
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In class 7 maths book on pg no 19 and 20 ( ch 1 integers) there is an example 3 verify (-30)×[13 (-3)]=[(-30)×13] [(-30)×(-3)] Can anyone tell me that how it has solved? Plzz?
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