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A three phase transmission line having conductors each of resistance 1.0 Ω/km is supplying a load of 15 MW at 0.8 power factor lagging. The receiving end voltage is 120 kV. The losses in the transmission line is found to be 15% of load. The distance over which the load supplied is ______ (in km)
    Correct answer is between '91.5,93'. Can you explain this answer?
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    Verified Answer
    A three phase transmission line having conductors each of resistance 1...
    P = 15 MW
    Power factor = 0.8 lagging
    R = 1 Ω/km
    VR = 120 kV
    Line losses = 
    Line current 
     
    Line losses = 3I2R = 2.25×10 6
    Length of line = 92.16 km
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    Most Upvoted Answer
    A three phase transmission line having conductors each of resistance 1...
    Ohm and inductance 1.2 mH per km is delivering 5 MW at 220 kV and 0.8 power factor lagging. The length of the line is 150 km. Determine the regulation of the line.

    Solution:

    Given data:

    Resistance of each conductor = 1.0 ohm

    Inductance of each conductor = 1.2 mH/km

    Power delivered = 5 MW

    Voltage = 220 kV

    Power factor = 0.8 lagging

    Length of the line = 150 km

    First, we need to calculate the line impedance per phase:

    Z = R + jX

    where,

    R = resistance per km

    X = inductance per km

    Z = √(R² + X²)

    Z = √((1.0 ohm/km)² + (1.2 mH/km)²)

    Z = 1.44 + j0.001728 ohm/km

    Z(phase) = (1.44 + j0.001728) * 150 km

    Z(phase) = 216 + j0.2592 ohm

    Next, we need to calculate the load impedance:

    P = VI cos(θ)

    Q = VI sin(θ)

    S = VI*

    where,

    P = active power delivered = 5 MW

    V = line voltage = 220 kV

    cos(θ) = power factor = 0.8 lagging

    Q = reactive power delivered = 4.0 MW

    S = apparent power delivered = √(P² + Q²) = 6.25 MVA

    Z(load) = V² / S

    Z(load) = (220 kV)² / 6.25 MVA

    Z(load) = 7.744 ohm

    Now, we can calculate the voltage drop:

    V(drop) = I(load) * Z(total)

    where,

    I(load) = S / V = 28.41 A

    Z(total) = Z(phase) + Z(load)

    Z(total) = (216 + j0.2592) + 7.744

    Z(total) = 224.744 + j0.2592 ohm

    V(drop) = (28.41 A) * (224.744 + j0.2592) ohm

    V(drop) = 6,391 + j7.3592 kV

    Finally, we can calculate the regulation:

    Regulation = (V(drop) / V) * 100

    Regulation = ((6,391 + j7.3592 kV) / 220 kV) * 100

    Regulation = 2.90% + j3.34%
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    it depends on the length of the conductor the capacitance of the line is proportional to the length of the transmission line their effect is negligible on the performance of short having a length less than 80 km and low voltage transmission accidents of the transmission line along with the conductances forms the shunted mittens the conductance and the transmission line is because of the leakage over the surface of the conductor considered a line consisting of two conductors and be each of radius are the distance between the conductors being Des shown in the diagram below minus the potential difference between the conductors and via's work QA charge on conductor QB charge on conductor vvab pencil difference between conductor and the Epsilon minus absolute primitivity QA plus QV = 0 so that QA equals QB - equals DBA equals data equals DB equals our substituting these values and voltage equation we get the capacitance between the conductors is cab is referred to as lying to line capacitance if the two conductors are in VR oppositely charge then the potential difference between them is zero then the potential of each conductor is given by one half bath the capacitance between each conductor and point of zero potential and is capacitive CN is called the capacitance to neut or capacitance to ground capacitance cab is the combination of two equal capacity and VN series thus capacitance to neutral is twice the capacitance between the conductors IE CN equals to Cave the absolute primitivity Epsilon is given by Epsilon equals epsilono Epsilon are where epsilano is the permittivity of the free space and Epsilon or is the relative primitivity of the medium prayer capacitance reactants between one conductor and neutral capacitance of the symmetrical three phase line let a balanced system of voltage be applied to a symmetrical three-phase line shown below the phasor diagram of the three phase line with equilateral spacing is shown below take the voltage of conductor to neutral as a reference phaser the potential difference between conductor and we can be written the similarly potential difference between conductors and sea is on adding equations one and two we get also combining equation three and four from equation 6 and 7 the line to neutral capacitance the capacitance of symmetrical three phase line is same as that of the two wire line Related: Capacitance of Transmission Lines?

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    A three phase transmission line having conductors each of resistance 1.0 Ω/km is supplying a load of 15 MW at 0.8 power factor lagging. The receiving end voltage is 120 kV. The losses in the transmission line is found to be 15% of load. The distance over which the load supplied is ______ (in km)Correct answer is between '91.5,93'. Can you explain this answer?
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    A three phase transmission line having conductors each of resistance 1.0 Ω/km is supplying a load of 15 MW at 0.8 power factor lagging. The receiving end voltage is 120 kV. The losses in the transmission line is found to be 15% of load. The distance over which the load supplied is ______ (in km)Correct answer is between '91.5,93'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A three phase transmission line having conductors each of resistance 1.0 Ω/km is supplying a load of 15 MW at 0.8 power factor lagging. The receiving end voltage is 120 kV. The losses in the transmission line is found to be 15% of load. The distance over which the load supplied is ______ (in km)Correct answer is between '91.5,93'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A three phase transmission line having conductors each of resistance 1.0 Ω/km is supplying a load of 15 MW at 0.8 power factor lagging. The receiving end voltage is 120 kV. The losses in the transmission line is found to be 15% of load. The distance over which the load supplied is ______ (in km)Correct answer is between '91.5,93'. Can you explain this answer?.
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