Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider the statementdo{i = i + 1;}While(a[i...
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Consider the statement
do
{
i = i + 1;
}
While(a[i] < b);
The minimum number of variables required in three address code of the above statement is _____.
Correct answer is '3'. Can you explain this answer?
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Verified Answer
Consider the statementdo{i = i + 1;}While(a[i] < b);The minimum num...
t1 = i + 1
i = t1
t2 = i * 8 // refers memory allocation for given data type
t3 = a[t2]
if t3 < b
Hence, 3 variables are required in three address code.
Most Upvoted Answer
Consider the statementdo{i = i + 1;}While(a[i] < b);The minimum num...
Understanding the Statement
The given statement is a loop structure that increments an index `i` while checking a condition involving an array `a` and a variable `b`. The pseudocode can be translated into three-address code.
Variables Breakdown
To analyze the number of variables required, we need to identify the components involved in the loop:
- Loop Index Variable:
- The variable `i` is essential for tracking the current index of the array `a`.
- Array Access:
- Accessing the array requires the index `i` to fetch `a[i]`.
- Comparison Variable:
- The variable `b` is used for comparison in the condition `a[i] < b`.="" this="" means="" `b`="" must="" also="" be="" referenced="" in="" the="" />
Three-Address Code Representation
The three-address code representation of the loop can be broken down as follows:
1. Increment Operation:
- `i = i + 1;` - This line increments the index `i`.
2. Condition Check:
- The condition check `a[i] < b`="" needs="" to="" evaluate="" whether="" the="" value="" at="" the="" current="" index="" of="" `a`="" is="" less="" than="" />
In the three-address code format, a typical representation might be:
- `t1 = a[i]` (Temporary variable `t1` holds the value of `a[i]`)
- `t2 = t1 < b`="" (temporary="" variable="" `t2`="" stores="" the="" result="" of="" the="" />
- `if t2 goto` (Conditional jump based on the comparison result)
Conclusion: Minimum Variables Required
In total, the minimum number of variables required is:
- `i` (for indexing)
- `b` (for comparison)
- Temporary variables (for storing intermediate results)
Thus, in summary, the minimum variables required in three-address code for the given statement is 3 (i, b, and a temporary variable for the condition check).
The given statement is a loop structure that increments an index `i` while checking a condition involving an array `a` and a variable `b`. The pseudocode can be translated into three-address code.
Variables Breakdown
To analyze the number of variables required, we need to identify the components involved in the loop:
- Loop Index Variable:
- The variable `i` is essential for tracking the current index of the array `a`.
- Array Access:
- Accessing the array requires the index `i` to fetch `a[i]`.
- Comparison Variable:
- The variable `b` is used for comparison in the condition `a[i] < b`.="" this="" means="" `b`="" must="" also="" be="" referenced="" in="" the="" />
Three-Address Code Representation
The three-address code representation of the loop can be broken down as follows:
1. Increment Operation:
- `i = i + 1;` - This line increments the index `i`.
2. Condition Check:
- The condition check `a[i] < b`="" needs="" to="" evaluate="" whether="" the="" value="" at="" the="" current="" index="" of="" `a`="" is="" less="" than="" />
In the three-address code format, a typical representation might be:
- `t1 = a[i]` (Temporary variable `t1` holds the value of `a[i]`)
- `t2 = t1 < b`="" (temporary="" variable="" `t2`="" stores="" the="" result="" of="" the="" />
- `if t2 goto
Conclusion: Minimum Variables Required
In total, the minimum number of variables required is:
- `i` (for indexing)
- `b` (for comparison)
- Temporary variables (for storing intermediate results)
Thus, in summary, the minimum variables required in three-address code for the given statement is 3 (i, b, and a temporary variable for the condition check).
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Consider the statementdo{i = i + 1;}While(a[i] < b);The minimum number of variables required in three address code of the above statement is _____.Correct answer is '3'. Can you explain this answer?
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