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A uniform line charge of infinite length with PL = 15 nC/m lies along the z-axis.
The electric field at (5, 12, 20) will be – v/m
    Correct answer is between '20.5,21'. Can you explain this answer?
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    A uniform line charge of infinite length with PL= 15 nC/m lies along t...
    Electric field at a point P(x, y, z) is given as
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    A uniform line charge of infinite length with PL= 15 nC/m lies along t...
    We can use the formula for the electric field due to a line charge at a point P in space, which is given by:

    E = kλ / r

    where k is Coulomb's constant (k = 9 x 10^9 N.m^2/C^2), λ is the charge density (in C/m), and r is the distance from the point P to the line charge.

    In this case, the line charge is along the z-axis, so the distance from the point P(5, 12, 20) to the line charge is simply the distance from P to the z-axis, which is:

    r = √(5^2 + 12^2) = √(169) = 13 m

    The charge density is given as λ = 15 nC/m = 15 x 10^-9 C/m.

    Substituting these values into the formula, we get:

    E = (9 x 10^9 N.m^2/C^2) x (15 x 10^-9 C/m) / 13 m

    E = 10.38 N/C

    Therefore, the electric field at point P(5, 12, 20) is 10.38 N/C, directed along the radial direction from the line charge towards the point P.
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    A uniform line charge of infinite length with PL= 15 nC/m lies along the z-axis.The electric field at (5, 12, 20) will be – v/mCorrect answer is between '20.5,21'. Can you explain this answer?
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