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Under high electric fields, in a semiconductor with increasing electric field,
- a)The mobility of charge carriers decrease
- b)The mobility of charge carriers Increase
- c)The velocity of charge carriers not saturates
- d)The velocity of charge carriers Increases.
Correct answer is option 'A'. Can you explain this answer?
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Under high electric fields, in a semiconductor with increasing electri...
we known that
V = μE
μ = constant when E < 103 V/cm
when 103 < E < 104 V/cm
when 103 < E < 104 V/cm
when E > 104 V/cm∴ When E Increase mobility decrease.
Most Upvoted Answer
Under high electric fields, in a semiconductor with increasing electri...
Explanation:
Under high electric fields, the mobility of charge carriers decreases in a semiconductor. This is due to the following reasons:
Impact ionization:
When an electric field is applied to a semiconductor, there is a chance for the electrons to gain enough energy to collide with the atoms and create electron-hole pairs. This process is called impact ionization. The newly created electron-hole pairs become additional charge carriers and increase the current flow. However, this process also reduces the mobility of the existing charge carriers.
Scattering:
As the electric field increases, the charge carriers experience more scattering due to the interaction with impurities, phonons, and other charge carriers. This reduces the mean free path of the charge carriers and hence their mobility.
Velocity saturation:
The velocity of charge carriers increases with the electric field, but it eventually saturates due to the scattering and the limited mean free path. This means that the charge carriers cannot gain more kinetic energy beyond a certain limit, and hence their mobility decreases.
Conclusion:
Hence, under high electric fields, the mobility of charge carriers decreases in a semiconductor due to impact ionization, scattering, and velocity saturation.
Under high electric fields, the mobility of charge carriers decreases in a semiconductor. This is due to the following reasons:
Impact ionization:
When an electric field is applied to a semiconductor, there is a chance for the electrons to gain enough energy to collide with the atoms and create electron-hole pairs. This process is called impact ionization. The newly created electron-hole pairs become additional charge carriers and increase the current flow. However, this process also reduces the mobility of the existing charge carriers.
Scattering:
As the electric field increases, the charge carriers experience more scattering due to the interaction with impurities, phonons, and other charge carriers. This reduces the mean free path of the charge carriers and hence their mobility.
Velocity saturation:
The velocity of charge carriers increases with the electric field, but it eventually saturates due to the scattering and the limited mean free path. This means that the charge carriers cannot gain more kinetic energy beyond a certain limit, and hence their mobility decreases.
Conclusion:
Hence, under high electric fields, the mobility of charge carriers decreases in a semiconductor due to impact ionization, scattering, and velocity saturation.
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Under high electric fields, in a semiconductor with increasing electric field,a)The mobility of charge carriers decreaseb)The mobility of charge carriers Increasec)The velocity of charge carriers not saturatesd)The velocity of charge carriers Increases.Correct answer is option 'A'. Can you explain this answer?
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