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A uniformly distributed load of 80 kN per meter run of length 3 m moves on a simply support girder of span 10 m. The magnitude of the ratio of Maximum negative shear force to the maximum positive shear force at 4 m from the left end will be _______ (up to two decimal places).
    Correct answer is between '0.54,0.56'. Can you explain this answer?
    Verified Answer
    A uniformly distributed load of 80 kN per meter run of length 3 m move...
    For maximum positive shear force at C:
    Using Muller Breslau Principle.
    y13=356y13=356
    Y1 = 0.3
    Maximum positive shear force at  (S.F)max1 =108kN
    For maximum negative shear force at C:

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    Most Upvoted Answer
    A uniformly distributed load of 80 kN per meter run of length 3 m move...
    To determine the maximum negative and positive shear forces at a particular location on the girder, we need to consider the effect of the uniformly distributed load and the span of the girder.

    Let's analyze the girder and calculate the maximum negative and positive shear forces at 4 m from the left end.

    1. Determine the reactions at the supports:
    - Since the girder is simply supported, the reactions at the supports will be equal.
    - The total load acting on the girder is the product of the uniformly distributed load and the span length: 80 kN/m * 10 m = 800 kN.
    - Therefore, each support will have a reaction of 800 kN / 2 = 400 kN.

    2. Calculate the shear force due to the uniformly distributed load:
    - At any point on the girder, the shear force due to the uniformly distributed load is equal to the product of the load intensity and the distance from the point to the nearest support.
    - At 4 m from the left end, the distance to the nearest support is 4 m.
    - Therefore, the shear force due to the uniformly distributed load at this location is 80 kN/m * 4 m = 320 kN.

    3. Calculate the maximum positive shear force:
    - The maximum positive shear force occurs at the left support and is equal to the reaction at that support, which is 400 kN.

    4. Calculate the maximum negative shear force:
    - The maximum negative shear force occurs at the right support and is equal to the reaction at that support, which is also 400 kN.

    5. Calculate the ratio of the maximum negative shear force to the maximum positive shear force:
    - The ratio is given by: Maximum Negative Shear Force / Maximum Positive Shear Force.
    - Substituting the values, we get: 400 kN / 400 kN = 1.

    Based on the calculations, the ratio of the maximum negative shear force to the maximum positive shear force at 4 m from the left end is 1. However, the correct answer is given as between 0.54 and 0.56.

    This discrepancy can be explained by considering the distribution of the shear force along the girder. The shear force is not constant and changes linearly with distance. At 4 m from the left end, the shear force due to the uniformly distributed load is 320 kN. As we move towards the right end, the shear force decreases linearly until it reaches 0 at the right support. Therefore, the maximum negative shear force will be less than 320 kN, resulting in a ratio less than 1.

    To find the exact value of the ratio, we need to consider the shear force distribution along the girder. This can be done by using the equations of static equilibrium and shear force diagrams. By integrating the shear force equation, we can determine the exact value of the maximum negative shear force and calculate the ratio.

    Unfortunately, without the shear force distribution equation or additional information, it is not possible to determine the exact value of the ratio. The given range of 0.54 to 0.56 suggests that a more detailed analysis or structural software may have been used to obtain a more accurate result.
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    A uniformly distributed load of 80 kN per meter run of length 3 m moves on a simply support girder of span 10 m. The magnitude of the ratio of Maximum negative shear force to the maximum positive shear force at 4 m from the left end will be _______ (up to two decimal places).Correct answer is between '0.54,0.56'. Can you explain this answer?
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    A uniformly distributed load of 80 kN per meter run of length 3 m moves on a simply support girder of span 10 m. The magnitude of the ratio of Maximum negative shear force to the maximum positive shear force at 4 m from the left end will be _______ (up to two decimal places).Correct answer is between '0.54,0.56'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A uniformly distributed load of 80 kN per meter run of length 3 m moves on a simply support girder of span 10 m. The magnitude of the ratio of Maximum negative shear force to the maximum positive shear force at 4 m from the left end will be _______ (up to two decimal places).Correct answer is between '0.54,0.56'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniformly distributed load of 80 kN per meter run of length 3 m moves on a simply support girder of span 10 m. The magnitude of the ratio of Maximum negative shear force to the maximum positive shear force at 4 m from the left end will be _______ (up to two decimal places).Correct answer is between '0.54,0.56'. Can you explain this answer?.
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