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It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared
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the Civil Engineering (CE) exam syllabus. Information about It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer?.
Solutions for It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
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Here you can find the meaning of It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice It is given that:Modulus of elasticity of cement concrete = 210 × 103kg/cm2Poisson’s ratio for concrete = 0.20Modulus of subgrade reaction, K = 5 kg/m3Radius of wheel load distribution = 15 cm.Slab thickness = 20 cmThe distance from the apex of slab corner to section of maximum stress along the corner bisector is,a)74 cmb)99 cmc)86 cmd)79 cmCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.