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A shunt motor 500 V, draw 40 A while supplying rated load at speed of 120 rad/sec. The armature resistance is 2 Ω and field winding resistance 250 Ω, external resistance is inserted in series with the armature circuit so that armature current does not exceed 160% of its rated value when the motor is plugged. The breaking torque at the instant of plugging is _____ N-m
    Correct answer is between '347,352'. Can you explain this answer?
    Verified Answer
    A shunt motor 500 V, draw 40 A while supplying rated load at speed of ...
    Field current 
     
    I = 40 – 2 = 38 A
    Ea = 500 – 38 × 2 = 424 V
    At the instant of plugging
    Plugging torque =
    = 214.83 N-m
    Load torque​ 
    ∴ Braking torque = 214.83 + 134.27
    = 349.1 N-m
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    Most Upvoted Answer
    A shunt motor 500 V, draw 40 A while supplying rated load at speed of ...
    The armature resistance given is 2 ohms.

    To find the back EMF, we can use the formula:

    Eb = V - Ia * Ra

    Where:
    Eb = back EMF
    V = supply voltage = 500 V
    Ia = armature current = 40 A
    Ra = armature resistance = 2 ohms

    Eb = 500 V - (40 A * 2 ohms)
    Eb = 500 V - 80 V
    Eb = 420 V

    The back EMF of the shunt motor is 420 V.
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    A shunt motor 500 V, draw 40 A while supplying rated load at speed of 120 rad/sec. The armature resistance is 2 Ω and field winding resistance 250 Ω, external resistance is inserted in series with the armature circuit so that armature current does not exceed 160% of its rated value when the motor is plugged. The breaking torque at the instant of plugging is _____ N-mCorrect answer is between '347,352'. Can you explain this answer?
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    A shunt motor 500 V, draw 40 A while supplying rated load at speed of 120 rad/sec. The armature resistance is 2 Ω and field winding resistance 250 Ω, external resistance is inserted in series with the armature circuit so that armature current does not exceed 160% of its rated value when the motor is plugged. The breaking torque at the instant of plugging is _____ N-mCorrect answer is between '347,352'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A shunt motor 500 V, draw 40 A while supplying rated load at speed of 120 rad/sec. The armature resistance is 2 Ω and field winding resistance 250 Ω, external resistance is inserted in series with the armature circuit so that armature current does not exceed 160% of its rated value when the motor is plugged. The breaking torque at the instant of plugging is _____ N-mCorrect answer is between '347,352'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shunt motor 500 V, draw 40 A while supplying rated load at speed of 120 rad/sec. The armature resistance is 2 Ω and field winding resistance 250 Ω, external resistance is inserted in series with the armature circuit so that armature current does not exceed 160% of its rated value when the motor is plugged. The breaking torque at the instant of plugging is _____ N-mCorrect answer is between '347,352'. Can you explain this answer?.
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