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Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]
- a)50.00 u
- b)12.25 u
- c)6.50 u
- d)25.00 u
Correct answer is option 'B'. Can you explain this answer?
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Two gases A and B having the same volume diffuse through a porous part...
Most Upvoted Answer
Two gases A and B having the same volume diffuse through a porous part...
Given:
- The volume of gases A and B is the same.
- Gas A takes 20 seconds to diffuse through the porous partition.
- Gas B takes 10 seconds to diffuse through the porous partition.
- Molecular mass of gas A is 49 u.
To find:
The molecular mass of gas B.
Solution:
To solve this problem, we can use Graham's law of diffusion. According to Graham's law, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Mathematically, the rate of diffusion (R) is given by:
R ∝ 1/√M
where R is the rate of diffusion and M is the molar mass.
Step 1:
Let's assume that the rate of diffusion of gas A is R1 and the rate of diffusion of gas B is R2.
Given that R1 = 1/20 and R2 = 1/10 (since A takes 20 seconds to diffuse and B takes 10 seconds to diffuse)
Step 2:
According to Graham's law, the rate of diffusion is inversely proportional to the square root of the molar mass.
So, we can write:
R1/R2 = √(M2/M1)
where M1 and M2 are the molar masses of gases A and B, respectively.
Substituting the given values, we have:
1/20 / 1/10 = √(M2/49)
Simplifying the equation:
1/2 = √(M2/49)
Step 3:
Now, let's square both sides of the equation to eliminate the square root:
(1/2)^2 = (√(M2/49))^2
1/4 = M2/49
Cross multiplying:
M2 = 49/4 = 12.25
Answer:
The molecular mass of gas B is 12.25 u, which corresponds to option B.
- The volume of gases A and B is the same.
- Gas A takes 20 seconds to diffuse through the porous partition.
- Gas B takes 10 seconds to diffuse through the porous partition.
- Molecular mass of gas A is 49 u.
To find:
The molecular mass of gas B.
Solution:
To solve this problem, we can use Graham's law of diffusion. According to Graham's law, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Mathematically, the rate of diffusion (R) is given by:
R ∝ 1/√M
where R is the rate of diffusion and M is the molar mass.
Step 1:
Let's assume that the rate of diffusion of gas A is R1 and the rate of diffusion of gas B is R2.
Given that R1 = 1/20 and R2 = 1/10 (since A takes 20 seconds to diffuse and B takes 10 seconds to diffuse)
Step 2:
According to Graham's law, the rate of diffusion is inversely proportional to the square root of the molar mass.
So, we can write:
R1/R2 = √(M2/M1)
where M1 and M2 are the molar masses of gases A and B, respectively.
Substituting the given values, we have:
1/20 / 1/10 = √(M2/49)
Simplifying the equation:
1/2 = √(M2/49)
Step 3:
Now, let's square both sides of the equation to eliminate the square root:
(1/2)^2 = (√(M2/49))^2
1/4 = M2/49
Cross multiplying:
M2 = 49/4 = 12.25
Answer:
The molecular mass of gas B is 12.25 u, which corresponds to option B.
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Community Answer
Two gases A and B having the same volume diffuse through a porous part...
"B" is correct
by using Graham's diffusion law..
by using Graham's diffusion law..
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Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer?
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Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer?.
Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer?.
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Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be : [2011]a)50.00 ub)12.25 uc)6.50 ud)25.00 uCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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