Class 11 Exam > Class 11 Questions > 20 ℓ of SO2, diffuses through a porous ...
Start Learning for Free
20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :
- a)12.14 ℓ
- b)14.14 ℓ
- c)18.14 ℓ
- d)28.14 ℓ
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
20 ℓ of SO2, diffuses through a porous partition in 60 seconds. ...
The answer is 14.14 Litres.
Given: Volume of SO2=20 liter, Time taken for diffusion by SO2= 60 sec, Time taken for diffusion by O2= 30 sec.
To find: Volume of O2
Solution:
Let the volume of O2 be V
Rate of diffusion of SO2=20/60=1/3
Rate of diffusion of O2=V/30
We know, r1/r2=root of m2/root of m1 (where m1 and m2 are the molecular masses)
1/3/V/30=square root of 32/square root of 64
1/3* root 2=V/30
10*root 2=V
10*1.414=V
14.14 litres=V
i.e Volume of O2 is 14.14 litres
Most Upvoted Answer
20 ℓ of SO2, diffuses through a porous partition in 60 seconds. ...
Given:
Rate of diffusion of SO2 = 20 units
Time taken for diffusion of SO2 = 60 seconds
To find:
Volume of O2 diffused in 30 seconds
Approach:
We know that the rate of diffusion is inversely proportional to the square root of the molar mass of the gas. Therefore, the ratio of the rates of diffusion of two gases is given by the square root of the ratio of their molar masses.
Let's assume the molar mass of SO2 as M1 and the molar mass of O2 as M2.
From the given information, we can write the following equation:
Rate of diffusion of SO2 / Rate of diffusion of O2 = √(M2/M1)
We need to find the volume of O2 diffused in 30 seconds, which is directly proportional to the rate of diffusion.
Let's assume the volume of O2 diffused in 30 seconds as V.
From the above equation, we can write another equation:
Rate of diffusion of SO2 / Rate of diffusion of O2 = Volume of SO2 diffused / Volume of O2 diffused
Now, let's substitute the given values into the equations and solve for the volume of O2 diffused in 30 seconds.
Calculation:
Rate of diffusion of SO2 = 20 units
Time taken for diffusion of SO2 = 60 seconds
Rate of diffusion of O2 = ?
Volume of SO2 diffused = ?
Volume of O2 diffused = V
M1 = molar mass of SO2
M2 = molar mass of O2
Using the equation:
Rate of diffusion of SO2 / Rate of diffusion of O2 = √(M2/M1)
20 / Rate of diffusion of O2 = √(M2/M1)
Rate of diffusion of O2 = 20 / √(M2/M1)
Now, we know that the rate of diffusion is directly proportional to the volume of gas diffused.
Using the equation:
Rate of diffusion of SO2 / Rate of diffusion of O2 = Volume of SO2 diffused / Volume of O2 diffused
20 / Rate of diffusion of O2 = Volume of SO2 diffused / V
Volume of O2 diffused = V = (20 / Rate of diffusion of O2) * Volume of SO2 diffused
V = (20 / (20 / √(M2/M1))) * Volume of SO2 diffused
V = √(M2/M1) * Volume of SO2 diffused
Now, we need to find the ratio of the molar masses of O2 and SO2.
Molar mass of O2 = 32 g/mol
Molar mass of SO2 = 64 g/mol
M2/M1 = 32/64 = 1/2
Substituting this value into the equation:
V = √(1/2) * Volume of SO2 diffused
V = (√1 / √2) * Volume of SO2 diffused
V = (1 / √2) * Volume of SO2 diffused
Given that the volume of SO2 diffused in 60 seconds is 20 units, we can write:
Volume of SO2 diffused = 20
V = (1 / √2) * 20
V = (1
Rate of diffusion of SO2 = 20 units
Time taken for diffusion of SO2 = 60 seconds
To find:
Volume of O2 diffused in 30 seconds
Approach:
We know that the rate of diffusion is inversely proportional to the square root of the molar mass of the gas. Therefore, the ratio of the rates of diffusion of two gases is given by the square root of the ratio of their molar masses.
Let's assume the molar mass of SO2 as M1 and the molar mass of O2 as M2.
From the given information, we can write the following equation:
Rate of diffusion of SO2 / Rate of diffusion of O2 = √(M2/M1)
We need to find the volume of O2 diffused in 30 seconds, which is directly proportional to the rate of diffusion.
Let's assume the volume of O2 diffused in 30 seconds as V.
From the above equation, we can write another equation:
Rate of diffusion of SO2 / Rate of diffusion of O2 = Volume of SO2 diffused / Volume of O2 diffused
Now, let's substitute the given values into the equations and solve for the volume of O2 diffused in 30 seconds.
Calculation:
Rate of diffusion of SO2 = 20 units
Time taken for diffusion of SO2 = 60 seconds
Rate of diffusion of O2 = ?
Volume of SO2 diffused = ?
Volume of O2 diffused = V
M1 = molar mass of SO2
M2 = molar mass of O2
Using the equation:
Rate of diffusion of SO2 / Rate of diffusion of O2 = √(M2/M1)
20 / Rate of diffusion of O2 = √(M2/M1)
Rate of diffusion of O2 = 20 / √(M2/M1)
Now, we know that the rate of diffusion is directly proportional to the volume of gas diffused.
Using the equation:
Rate of diffusion of SO2 / Rate of diffusion of O2 = Volume of SO2 diffused / Volume of O2 diffused
20 / Rate of diffusion of O2 = Volume of SO2 diffused / V
Volume of O2 diffused = V = (20 / Rate of diffusion of O2) * Volume of SO2 diffused
V = (20 / (20 / √(M2/M1))) * Volume of SO2 diffused
V = √(M2/M1) * Volume of SO2 diffused
Now, we need to find the ratio of the molar masses of O2 and SO2.
Molar mass of O2 = 32 g/mol
Molar mass of SO2 = 64 g/mol
M2/M1 = 32/64 = 1/2
Substituting this value into the equation:
V = √(1/2) * Volume of SO2 diffused
V = (√1 / √2) * Volume of SO2 diffused
V = (1 / √2) * Volume of SO2 diffused
Given that the volume of SO2 diffused in 60 seconds is 20 units, we can write:
Volume of SO2 diffused = 20
V = (1 / √2) * 20
V = (1
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer?
Question Description
20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer?.
20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer?.
Solutions for 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 20 ℓ of SO2, diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :a)12.14 ℓb)14.14 ℓc)18.14 ℓd)28.14 ℓCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup