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A catchment having 6 rain gauge stations with the precipitation in the month of July is measured as P1 = 600 mm, P2 = 550 mm, P3 = 625 mm, P4 = 475 mm, and P5= 400 mm. The sixth rain gauge station was inoperative during this period. The weight area factor for first four rain gauge station is 0.1, 0.35, 0.16 and 0.15 respectively. If the weight area factor for remaining two rain gauge station are equal, then the Thiessen mean value (in mm, up to two decimal places) of the rainfall is ______. It is given that normal annual precipitation at the different 6 rain gauge station is N1 = 800, N2 = 650 mm, N3 = 500 mm, N4 = 575 mm, N5 = 600 mm, N6 = 700 mm
    Correct answer is between '542,547'. Can you explain this answer?
    Verified Answer
    A catchment having 6 rain gauge stations with the precipitation in the...
    Let x be the weight area factor for the two unknown rain gauge station
    Sum of all weight area factor = 1
    ∴ 0.1 + 0.35 + 0.16 + 0.15 + x + x = 1
    ⇒ 2x = 0.24
    ⇒ x = 0.12.
    Rainfall data for 6th rain gauge station
    P6 = 607.45 mm
    ∴ Mean rainfall value
    = (600 × 0.1) + (550 × 0.35) + (625 × 0.16) + (475 × 0.15) + (400 × 0.12) + (607.45 × 0.12)
    = 544.64 mm
    Pmean = 544.64 mm
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    Most Upvoted Answer
    A catchment having 6 rain gauge stations with the precipitation in the...
    Calculation of Thiessen Mean Value


    To calculate the Thiessen mean value for the rainfall in the catchment, we need to consider the precipitation measurements and the weight area factors of the rain gauge stations.

    Step 1: Calculate the weight area factor for the sixth rain gauge station

    Since the weight area factors for the first four rain gauge stations are given as 0.1, 0.35, 0.16, and 0.15 respectively, and the weight area factors for the remaining two rain gauge stations are equal, we can calculate the weight area factor for the sixth rain gauge station as follows:

    Weight area factor for the sixth rain gauge station = 1 - (sum of weight area factors for the first four rain gauge stations)
    = 1 - (0.1 + 0.35 + 0.16 + 0.15)
    = 1 - 0.76
    = 0.24

    Step 2: Calculate the weighted rainfall for each rain gauge station

    The weighted rainfall for each rain gauge station can be calculated by multiplying the precipitation measurement by its corresponding weight area factor.

    Weighted rainfall for P1 = P1 * weight area factor for P1
    = 600 * 0.1
    = 60 mm

    Weighted rainfall for P2 = P2 * weight area factor for P2
    = 550 * 0.35
    = 192.5 mm

    Weighted rainfall for P3 = P3 * weight area factor for P3
    = 625 * 0.16
    = 100 mm

    Weighted rainfall for P4 = P4 * weight area factor for P4
    = 475 * 0.15
    = 71.25 mm

    Weighted rainfall for P5 = P5 * weight area factor for P5
    = 400 * 0.24
    = 96 mm

    Step 3: Calculate the Thiessen mean value

    The Thiessen mean value can be calculated by summing up all the weighted rainfall values and dividing it by the sum of the weight area factors.

    Thiessen mean value = (Sum of weighted rainfall values) / (Sum of weight area factors)
    = (60 + 192.5 + 100 + 71.25 + 96) / (0.1 + 0.35 + 0.16 + 0.15 + 0.24)
    = 519.75 / 1

    Rounded to two decimal places, the Thiessen mean value of the rainfall in the catchment is approximately 519.75 mm.

    This answer does not match the given range of 542-547 mm. Please recheck the calculations or any additional information provided.
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    A catchment having 6 rain gauge stations with the precipitation in the month of July is measured as P1= 600 mm, P2= 550 mm, P3= 625 mm, P4= 475 mm, and P5= 400 mm. The sixth rain gauge station was inoperative during this period. The weight area factor for first four rain gauge station is 0.1, 0.35, 0.16 and 0.15 respectively. If the weight area factor for remaining two rain gauge station are equal, then the Thiessen mean value (in mm, up to two decimal places) of the rainfall is ______. It is given that normal annual precipitation at the different 6 rain gauge station is N1= 800, N2= 650 mm, N3= 500 mm, N4= 575 mm, N5= 600 mm, N6= 700 mmCorrect answer is between '542,547'. Can you explain this answer?
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    A catchment having 6 rain gauge stations with the precipitation in the month of July is measured as P1= 600 mm, P2= 550 mm, P3= 625 mm, P4= 475 mm, and P5= 400 mm. The sixth rain gauge station was inoperative during this period. The weight area factor for first four rain gauge station is 0.1, 0.35, 0.16 and 0.15 respectively. If the weight area factor for remaining two rain gauge station are equal, then the Thiessen mean value (in mm, up to two decimal places) of the rainfall is ______. It is given that normal annual precipitation at the different 6 rain gauge station is N1= 800, N2= 650 mm, N3= 500 mm, N4= 575 mm, N5= 600 mm, N6= 700 mmCorrect answer is between '542,547'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A catchment having 6 rain gauge stations with the precipitation in the month of July is measured as P1= 600 mm, P2= 550 mm, P3= 625 mm, P4= 475 mm, and P5= 400 mm. The sixth rain gauge station was inoperative during this period. The weight area factor for first four rain gauge station is 0.1, 0.35, 0.16 and 0.15 respectively. If the weight area factor for remaining two rain gauge station are equal, then the Thiessen mean value (in mm, up to two decimal places) of the rainfall is ______. It is given that normal annual precipitation at the different 6 rain gauge station is N1= 800, N2= 650 mm, N3= 500 mm, N4= 575 mm, N5= 600 mm, N6= 700 mmCorrect answer is between '542,547'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A catchment having 6 rain gauge stations with the precipitation in the month of July is measured as P1= 600 mm, P2= 550 mm, P3= 625 mm, P4= 475 mm, and P5= 400 mm. The sixth rain gauge station was inoperative during this period. The weight area factor for first four rain gauge station is 0.1, 0.35, 0.16 and 0.15 respectively. If the weight area factor for remaining two rain gauge station are equal, then the Thiessen mean value (in mm, up to two decimal places) of the rainfall is ______. It is given that normal annual precipitation at the different 6 rain gauge station is N1= 800, N2= 650 mm, N3= 500 mm, N4= 575 mm, N5= 600 mm, N6= 700 mmCorrect answer is between '542,547'. Can you explain this answer?.
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