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What is the runoff coefficient of the catchment area of 140 km? that received 120 cm of rainfall in a year? At the outlet of the catchment, the flow in the stream draining the catchment was found to have an average rate of 1.5
m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months.
ANS 0.4224
?
m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months.
ANS 0.4224
?
Most Upvoted Answer
What is the runoff coefficient of the catchment area of 140 km? that r...
**Calculation of Runoff Coefficient**
The runoff coefficient (C) is a dimensionless parameter that represents the proportion of rainfall that becomes direct runoff. It is typically used in hydrological calculations to estimate the peak flow rate and volume of runoff from a catchment area.
To calculate the runoff coefficient, we need to know the catchment area (A) and the total rainfall (P) received in a year.
Given:
Catchment area (A) = 140 km^2
Total rainfall (P) = 120 cm
Step 1: Convert the catchment area from km^2 to m^2
1 km^2 = 1,000,000 m^2
So, the catchment area (A) = 140 × 1,000,000 = 140,000,000 m^2
Step 2: Convert the total rainfall from cm to m
1 cm = 0.01 m
So, the total rainfall (P) = 120 × 0.01 = 1.2 m
Step 3: Calculate the runoff coefficient using the formula:
C = Q / (A × P)
where Q is the total runoff volume.
**Calculation of Total Runoff Volume**
To calculate the total runoff volume, we need to determine the flow rate (Q) of the stream draining the catchment area for different time periods.
Given:
Flow rate for the first 3 months = 1.5 m^3/s
Flow rate for the next 6 months = 2.0 m^3/s
Flow rate for the remaining 3 months = 3.5 m^3/s
Step 1: Calculate the total runoff volume for each time period
Total runoff volume for the first 3 months = 1.5 m^3/s × (3 months × 30 days/month × 24 hours/day × 60 minutes/hour × 60 seconds/minute)
= 1.5 m^3/s × 2,592,000 s = 3,888,000 m^3
Total runoff volume for the next 6 months = 2.0 m^3/s × (6 months × 30 days/month × 24 hours/day × 60 minutes/hour × 60 seconds/minute)
= 2.0 m^3/s × 5,184,000 s = 10,368,000 m^3
Total runoff volume for the remaining 3 months = 3.5 m^3/s × (3 months × 30 days/month × 24 hours/day × 60 minutes/hour × 60 seconds/minute)
= 3.5 m^3/s × 2,592,000 s = 9,072,000 m^3
Step 2: Calculate the total runoff volume (Q) by summing up the volumes for each time period
Total runoff volume (Q) = 3,888,000 m^3 + 10,368,000 m^3 + 9,072,000 m^3 = 23,328,000 m^3
**Final Calculation of Runoff Coefficient**
Now, we can substitute the values of A and Q into the formula to calculate the runoff coefficient (C).
C = Q / (A × P)
C = 23,328,000 m^3 / (140,
The runoff coefficient (C) is a dimensionless parameter that represents the proportion of rainfall that becomes direct runoff. It is typically used in hydrological calculations to estimate the peak flow rate and volume of runoff from a catchment area.
To calculate the runoff coefficient, we need to know the catchment area (A) and the total rainfall (P) received in a year.
Given:
Catchment area (A) = 140 km^2
Total rainfall (P) = 120 cm
Step 1: Convert the catchment area from km^2 to m^2
1 km^2 = 1,000,000 m^2
So, the catchment area (A) = 140 × 1,000,000 = 140,000,000 m^2
Step 2: Convert the total rainfall from cm to m
1 cm = 0.01 m
So, the total rainfall (P) = 120 × 0.01 = 1.2 m
Step 3: Calculate the runoff coefficient using the formula:
C = Q / (A × P)
where Q is the total runoff volume.
**Calculation of Total Runoff Volume**
To calculate the total runoff volume, we need to determine the flow rate (Q) of the stream draining the catchment area for different time periods.
Given:
Flow rate for the first 3 months = 1.5 m^3/s
Flow rate for the next 6 months = 2.0 m^3/s
Flow rate for the remaining 3 months = 3.5 m^3/s
Step 1: Calculate the total runoff volume for each time period
Total runoff volume for the first 3 months = 1.5 m^3/s × (3 months × 30 days/month × 24 hours/day × 60 minutes/hour × 60 seconds/minute)
= 1.5 m^3/s × 2,592,000 s = 3,888,000 m^3
Total runoff volume for the next 6 months = 2.0 m^3/s × (6 months × 30 days/month × 24 hours/day × 60 minutes/hour × 60 seconds/minute)
= 2.0 m^3/s × 5,184,000 s = 10,368,000 m^3
Total runoff volume for the remaining 3 months = 3.5 m^3/s × (3 months × 30 days/month × 24 hours/day × 60 minutes/hour × 60 seconds/minute)
= 3.5 m^3/s × 2,592,000 s = 9,072,000 m^3
Step 2: Calculate the total runoff volume (Q) by summing up the volumes for each time period
Total runoff volume (Q) = 3,888,000 m^3 + 10,368,000 m^3 + 9,072,000 m^3 = 23,328,000 m^3
**Final Calculation of Runoff Coefficient**
Now, we can substitute the values of A and Q into the formula to calculate the runoff coefficient (C).
C = Q / (A × P)
C = 23,328,000 m^3 / (140,
Community Answer
What is the runoff coefficient of the catchment area of 140 km? that r...
0.42
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What is the runoff coefficient of the catchment area of 140 km? that received 120 cm of rainfall in a year? At the outlet of the catchment, the flow in the stream draining the catchment was found to have an average rate of 1.5m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months. ANS 0.4224?
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What is the runoff coefficient of the catchment area of 140 km? that received 120 cm of rainfall in a year? At the outlet of the catchment, the flow in the stream draining the catchment was found to have an average rate of 1.5m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months. ANS 0.4224? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about What is the runoff coefficient of the catchment area of 140 km? that received 120 cm of rainfall in a year? At the outlet of the catchment, the flow in the stream draining the catchment was found to have an average rate of 1.5m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months. ANS 0.4224? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the runoff coefficient of the catchment area of 140 km? that received 120 cm of rainfall in a year? At the outlet of the catchment, the flow in the stream draining the catchment was found to have an average rate of 1.5m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months. ANS 0.4224?.
What is the runoff coefficient of the catchment area of 140 km? that received 120 cm of rainfall in a year? At the outlet of the catchment, the flow in the stream draining the catchment was found to have an average rate of 1.5m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months. ANS 0.4224? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about What is the runoff coefficient of the catchment area of 140 km? that received 120 cm of rainfall in a year? At the outlet of the catchment, the flow in the stream draining the catchment was found to have an average rate of 1.5m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months. ANS 0.4224? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the runoff coefficient of the catchment area of 140 km? that received 120 cm of rainfall in a year? At the outlet of the catchment, the flow in the stream draining the catchment was found to have an average rate of 1.5m^3 for the first 3 months, 2.0 m^3/s for the next 6 months, and 3.5 m^3/s for the remaining 3 months. ANS 0.4224?.
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