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A PC-relative mode branch instruction is 8 bytes long. The address of the instruction, in decimal, is 548321. Find the branch target address if the signed displacement in the instruction is –29.
Correct answer is '548300'. Can you explain this answer?
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A PC-relative mode branch instruction is 8 bytes long. The address of ...
PC – relative mode branch instruction uses content of the program counter. Program counter points to the next instruction i.e. 548321 + 8 = 548329
Branch target address = 548329 – 29 = 548300.
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A PC-relative mode branch instruction is 8 bytes long. The address of ...
Unknown.
To find the branch target address, we need to first determine the signed displacement in the instruction. Since the instruction is 8 bytes long, the displacement is the last 6 bits of the instruction (bits 0-5), shifted left by 2 bits.
Let's assume that the displacement is stored in two's complement form. To convert the displacement to decimal, we first need to determine the sign of the displacement. The sign bit is the 6th bit (bit 5) of the instruction. If it is 1, then the displacement is negative; if it is 0, then the displacement is positive.
Let's say the sign bit is 1, indicating a negative displacement. To convert the displacement to decimal, we first need to invert all the bits and add 1 (this is the process for converting from two's complement to decimal). Then, we shift the result right by 2 bits, since the displacement is stored left-shifted by 2 bits.
So, let's assume the displacement is 0b111111 (binary). Inverting the bits gives us 0b000000, and adding 1 gives us 0b000001. Shifting this result right by 2 bits gives us 0b0000, which is decimal 0.
Therefore, the branch target address is the address of the instruction plus the displacement (in bytes), which is 548321 + 0 = 548321.
To find the branch target address, we need to first determine the signed displacement in the instruction. Since the instruction is 8 bytes long, the displacement is the last 6 bits of the instruction (bits 0-5), shifted left by 2 bits.
Let's assume that the displacement is stored in two's complement form. To convert the displacement to decimal, we first need to determine the sign of the displacement. The sign bit is the 6th bit (bit 5) of the instruction. If it is 1, then the displacement is negative; if it is 0, then the displacement is positive.
Let's say the sign bit is 1, indicating a negative displacement. To convert the displacement to decimal, we first need to invert all the bits and add 1 (this is the process for converting from two's complement to decimal). Then, we shift the result right by 2 bits, since the displacement is stored left-shifted by 2 bits.
So, let's assume the displacement is 0b111111 (binary). Inverting the bits gives us 0b000000, and adding 1 gives us 0b000001. Shifting this result right by 2 bits gives us 0b0000, which is decimal 0.
Therefore, the branch target address is the address of the instruction plus the displacement (in bytes), which is 548321 + 0 = 548321.
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A PC-relative mode branch instruction is 8 bytes long. The address of the instruction, in decimal, is 548321. Find the branch target address if the signed displacement in the instruction is –29.Correct answer is '548300'. Can you explain this answer?
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A PC-relative mode branch instruction is 8 bytes long. The address of the instruction, in decimal, is 548321. Find the branch target address if the signed displacement in the instruction is –29.Correct answer is '548300'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A PC-relative mode branch instruction is 8 bytes long. The address of the instruction, in decimal, is 548321. Find the branch target address if the signed displacement in the instruction is –29.Correct answer is '548300'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A PC-relative mode branch instruction is 8 bytes long. The address of the instruction, in decimal, is 548321. Find the branch target address if the signed displacement in the instruction is –29.Correct answer is '548300'. Can you explain this answer?.
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