Two Indian Standard Flat (ISF) 2 m long are to be jointed to make a member of 3 m through lap joint as shown in the figure below. The bolts are of 20 mm diameter and grade 4.6. The two plates to be jointed are 10 mm and 12 mm thick. The efficiency of the lap joint will be _____ %.(Use steel of grade Fe410)Correct answer is between '32,33.5'. Can you explain this answer?

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Two Indian Standard Flat (ISF) 2 m long are to be jointed to make a member of 3 m through lap joint as shown in the figure below. The bolts are of 20 mm diameter and grade 4.6. The two plates to be jointed are 10 mm and 12 mm thick. The efficiency of the lap joint will be _____ %.

(Use steel of grade Fe410)

Correct answer is between '32,33.5'. Can you explain this answer?

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Two Indian Standard Flat (ISF) 2 m long are to be jointed to make a me...

Given:

For Fe410 grade of steel: f_u = 410 MPa

For bolts of grade 4.6: f_ub = 400 MPa

Diameter of the bolt, d = 20 mm

Bolt-hole diameter (d_h or d_o) = 22 mm

Area of one bolt =

A_b = 314.16 mm²

The bolts will be under single shearing and bearing.

Strength of the bolt in single shear

= 58 kN

Strength of the joint per gauge length in shear

(since two bolts fall in one-gauge length)

= 2 × 58

= 116 kN

Strength of bolt in bearing

Where, t = thickness of thinner plate

r_mb = partial safety factor for

material of bolt = 1.25

K_b is least of

∴ k_b = 0.5

P_b = 89.38 kN

Strength of the joint per gauge length in bearing (two bolts fall lies in each gauge length)

= 2 × 89.38 = 178.76 kN

The net tensile strength of plate per pitch length,

⇒ P_t = 289.296 kN

Hence, the strength of the joint per pitch length = 116 kN

Strength of solid plate per gauge length

= 354.24 kN

Efficiency of the joint

= 32.75%

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Two Indian Standard Flat (ISF) 2 m long are to be jointed to make a member of 3 m through lap joint as shown in the figure below. The bolts are of 20 mm diameter and grade 4.6. The two plates to be jointed are 10 mm and 12 mm thick. The efficiency of the lap joint will be _____ %.(Use steel of grade Fe410)Correct answer is between '32,33.5'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Two Indian Standard Flat (ISF) 2 m long are to be jointed to make a member of 3 m through lap joint as shown in the figure below. The bolts are of 20 mm diameter and grade 4.6. The two plates to be jointed are 10 mm and 12 mm thick. The efficiency of the lap joint will be _____ %.(Use steel of grade Fe410)Correct answer is between '32,33.5'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two Indian Standard Flat (ISF) 2 m long are to be jointed to make a member of 3 m through lap joint as shown in the figure below. The bolts are of 20 mm diameter and grade 4.6. The two plates to be jointed are 10 mm and 12 mm thick. The efficiency of the lap joint will be _____ %.(Use steel of grade Fe410)Correct answer is between '32,33.5'. Can you explain this answer?.

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