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(CH3)2 C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH by [1993]
- a)Chromic acid
- b)NaOI
- c)Cu at 300°C
- d)KMnO4.
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
(CH3)2 C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH by [1993]a)Chro...
Chromic acid and KMnO4 will cleave the molecule at the site of double bond while Cu at 300°C cannot oxidise COCH3 
COOH. The only reagent suitable for this conversion is NaOI or NaOH + I2 (iodoform
test):
COOH. The only reagent suitable for this conversion is NaOI or NaOH + I2 (iodoformtest):
Most Upvoted Answer
(CH3)2 C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH by [1993]a)Chro...
°Cd)KMnO4 in acidic medium
The correct option is a) Chromic acid. Chromic acid (H2CrO4) is a strong oxidizing agent commonly used to oxidize organic compounds. It can convert alkenes to diols or ketones, and can also oxidize alcohols to aldehydes, ketones, or carboxylic acids. In this case, (CH3)2C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH (a carboxylic acid) by chromic acid. NaOI, Cu at 300°C, and KMnO4 in acidic medium are not typically used to oxidize alkenes to carboxylic acids.
The correct option is a) Chromic acid. Chromic acid (H2CrO4) is a strong oxidizing agent commonly used to oxidize organic compounds. It can convert alkenes to diols or ketones, and can also oxidize alcohols to aldehydes, ketones, or carboxylic acids. In this case, (CH3)2C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH (a carboxylic acid) by chromic acid. NaOI, Cu at 300°C, and KMnO4 in acidic medium are not typically used to oxidize alkenes to carboxylic acids.
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(CH3)2 C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH by [1993]a)Chromic acidb)NaOIc)Cu at 300°Cd)KMnO4.Correct answer is option 'B'. Can you explain this answer?
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(CH3)2 C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH by [1993]a)Chromic acidb)NaOIc)Cu at 300°Cd)KMnO4.Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about (CH3)2 C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH by [1993]a)Chromic acidb)NaOIc)Cu at 300°Cd)KMnO4.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (CH3)2 C = CHCOCH3 can be oxidized to (CH3)2C = CHCOOH by [1993]a)Chromic acidb)NaOIc)Cu at 300°Cd)KMnO4.Correct answer is option 'B'. Can you explain this answer?.
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