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When CH2 = CHCOOH is reduced with LiAlH4, the compound obtained is : 
  • a)
    CH3CH2CH2OH
  • b)
    CH3CH2CHO
  • c)
    CH3CH2COOH
  • d)
    CH2=CHCH2OH
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
When CH2 = CHCOOH is reduced with LiAlH4, the compound obtained is :a)...
LiAlH4 can reduce acid, aldehyde,ketone,ester,alkyl halide,etc but it can't reduce double or triple bond.
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When CH2 = CHCOOH is reduced with LiAlH4, the compound obtained is :a)...
Reduction of CH2 = CHCOOH with LiAlH4
Reducing the compound CH2 = CHCOOH with LiAlH4 involves the addition of hydrogen atoms to the carbon-carbon double bond, resulting in the formation of a new compound.

Compound Obtained
The compound obtained after the reduction of CH2 = CHCOOH with LiAlH4 is CH2=CHCH2OH.

Explanation
- The compound CH2 = CHCOOH is an unsaturated carboxylic acid with a carbon-carbon double bond.
- When it is reduced with LiAlH4, the double bond is saturated with hydrogen atoms, resulting in CH2=CHCH2OH.
- The LiAlH4 acts as a reducing agent, providing the necessary hydrogen atoms for the reduction reaction to occur.
- The final compound, CH2=CHCH2OH, is a saturated alcohol with a carbon-carbon single bond and a hydroxyl group.
Therefore, the correct compound obtained after the reduction of CH2 = CHCOOH with LiAlH4 is CH2=CHCH2OH.
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When CH2 = CHCOOH is reduced with LiAlH4, the compound obtained is :a)CH3CH2CH2OHb)CH3CH2CHOc)CH3CH2COOHd)CH2=CHCH2OHCorrect answer is option 'D'. Can you explain this answer?
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