In an examination of 7 subjects with maximum 100 marks in each,I score...
Analysis of Exam Scores
- Total Number of Subjects: 7
- Maximum Marks in Each Subject: 100
- Scored 40 in All Subjects
- Average Marks in 3 Subjects: 48
- Highest Marks among these 3 Subjects: 64
- Scored 35 in a Subject
Calculation of Average Marks in 3 Subjects
Let the marks scored in the 3 subjects be x, y, and z.
Average marks = (x + y + z) / 3 = 48
x + y + z = 144
Calculation of Highest Marks among 3 Subjects
Let the highest marks be a.
a <=>=>
Calculation of Minimum Number of Subjects Failed
Let the number of subjects failed be f.
Scored 40 in all subjects, so total marks = 7 x 40 = 280
Scored 35 in a subject, so total marks = 245
Marks scored in the remaining 6 subjects = 280 - 245 = 35 x 6 = 210
Marks scored in the 3 subjects = x + y + z = 144
Marks scored in the remaining 3 subjects = 210 - 144 = 66
Highest marks scored in the 3 subjects = a
Total marks scored in all 7 subjects = 245 + 144 + a = 389 + a
Maximum possible marks = 7 x 100 = 700
Minimum marks required to pass = 33% of 700 = 231
Marks scored = 389 + a
Failed in (7 - f) subjects
Marks scored in failed subjects = 40 x f
Marks scored in passed subjects = (389 + a) - (40 x f)
Marks scored in passed subjects >= 231
(389 + a) - (40 x f) >= 231
149 + a >= 40 x f
a >= 40 x f - 149
From the above equations, we can conclude that:
- If a = 64, then f = 3
- If a = 63, then f = 3
- If a = 62, then f = 2
- If a = 61, then f = 2
- If a < 61,="" then="" f="" />
Conclusion
The minimum number of subjects in which the person failed is 1. This is because even if the person had scored the minimum marks (35) in the subject where he/she failed, the person would have passed as the total marks scored (389 + 35 = 424) is greater than the minimum