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Which of the following complex compounds will exhibit highest paramagnetic behaviour? [2011M] (At. No. : Ti = 22, Cr = 24, Co = 27, Zn = 30)
- a)[Ti (NH3)6]3+
- b)[Cr (NH3)6]3+
- c)[Co (NH3)6]3+
- d)[Zn (NH3)6]2+
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Which of the following complex compounds will exhibit highest paramagn...
(a) [Ti(NH3)6]3+ : 3d1 configuration and thus has one unpaired electron. (b) [Cr(NH3)6]3+ : In this complex Cr is in +3 oxidation state.
Thus, the complex is paramagnetic.
(c) [Co(NH3)6]3+ : In this complex are cobalt ion is in + 3 oxidation state with 3d6 configuration.
Co3+,[Ar]3d6
Co3+,[Ar]3d6
(inner orbital or d2sp3 hybrid orbital low spin complex) diamagnetic
(d) In this complex Zn exists as
Zn++ ion
Zn++ ion : 3d10 4s0
Due to presence of paired electrons complex is diamagnetic in nature.
Most Upvoted Answer
Which of the following complex compounds will exhibit highest paramagn...
Solution:
In order to determine which complex compound exhibits the highest paramagnetic behavior, we need to analyze the electronic configuration of each central metal ion. Paramagnetic behavior is a result of the presence of unpaired electrons in the d-orbitals of the metal ion.
- [Ti(NH3)6]3+:
The atomic number of Ti is 22. The electronic configuration of Ti is [Ar] 3d2 4s2. In the complex, Ti is in the +3 oxidation state, which means it has lost 3 electrons. Therefore, the electronic configuration of [Ti(NH3)6]3+ is [Ar] 3d0 4s0. Since there are no unpaired electrons, this complex is diamagnetic.
- [Cr(NH3)6]3+:
The atomic number of Cr is 24. The electronic configuration of Cr is [Ar] 3d5 4s1. In the complex, Cr is in the +3 oxidation state, which means it has lost 3 electrons. Therefore, the electronic configuration of [Cr(NH3)6]3+ is [Ar] 3d3 4s0. There are three unpaired electrons in the d-orbitals of Cr, making this complex paramagnetic.
- [Co(NH3)6]3+:
The atomic number of Co is 27. The electronic configuration of Co is [Ar] 3d7 4s2. In the complex, Co is in the +3 oxidation state, which means it has lost 3 electrons. Therefore, the electronic configuration of [Co(NH3)6]3+ is [Ar] 3d4 4s0. There are four unpaired electrons in the d-orbitals of Co, making this complex more paramagnetic than [Cr(NH3)6]3+.
- [Zn(NH3)6]2+:
The atomic number of Zn is 30. The electronic configuration of Zn is [Ar] 3d10 4s2. In the complex, Zn is in the +2 oxidation state, which means it has lost 2 electrons. Therefore, the electronic configuration of [Zn(NH3)6]2+ is [Ar] 3d10 4s0. Since there are no unpaired electrons, this complex is diamagnetic.
Conclusion:
Among the given complex compounds, [Cr(NH3)6]3+ exhibits the highest paramagnetic behavior due to the presence of three unpaired electrons in the d-orbitals of the central Cr ion.
In order to determine which complex compound exhibits the highest paramagnetic behavior, we need to analyze the electronic configuration of each central metal ion. Paramagnetic behavior is a result of the presence of unpaired electrons in the d-orbitals of the metal ion.
- [Ti(NH3)6]3+:
The atomic number of Ti is 22. The electronic configuration of Ti is [Ar] 3d2 4s2. In the complex, Ti is in the +3 oxidation state, which means it has lost 3 electrons. Therefore, the electronic configuration of [Ti(NH3)6]3+ is [Ar] 3d0 4s0. Since there are no unpaired electrons, this complex is diamagnetic.
- [Cr(NH3)6]3+:
The atomic number of Cr is 24. The electronic configuration of Cr is [Ar] 3d5 4s1. In the complex, Cr is in the +3 oxidation state, which means it has lost 3 electrons. Therefore, the electronic configuration of [Cr(NH3)6]3+ is [Ar] 3d3 4s0. There are three unpaired electrons in the d-orbitals of Cr, making this complex paramagnetic.
- [Co(NH3)6]3+:
The atomic number of Co is 27. The electronic configuration of Co is [Ar] 3d7 4s2. In the complex, Co is in the +3 oxidation state, which means it has lost 3 electrons. Therefore, the electronic configuration of [Co(NH3)6]3+ is [Ar] 3d4 4s0. There are four unpaired electrons in the d-orbitals of Co, making this complex more paramagnetic than [Cr(NH3)6]3+.
- [Zn(NH3)6]2+:
The atomic number of Zn is 30. The electronic configuration of Zn is [Ar] 3d10 4s2. In the complex, Zn is in the +2 oxidation state, which means it has lost 2 electrons. Therefore, the electronic configuration of [Zn(NH3)6]2+ is [Ar] 3d10 4s0. Since there are no unpaired electrons, this complex is diamagnetic.
Conclusion:
Among the given complex compounds, [Cr(NH3)6]3+ exhibits the highest paramagnetic behavior due to the presence of three unpaired electrons in the d-orbitals of the central Cr ion.
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Which of the following complex compounds will exhibit highest paramagnetic behaviour? [2011M] (At. No. : Ti = 22, Cr = 24, Co = 27, Zn = 30)a)[Ti (NH3)6]3+b)[Cr (NH3)6]3+c)[Co (NH3)6]3+d)[Zn (NH3)6]2+Correct answer is option 'B'. Can you explain this answer?
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