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Consider Fraunhoffer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference (in radians) between the wavelets from the opposite edges of the slit is
  • a)
    π / 4
  • b)
    π / 2
  • c)
    2 π
  • d)
    π
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Consider Fraunhoffer diffraction pattern obtained with a single slit i...
Path difference between the opposite edges is λ.
For a phase difference of 2π we get a path diff. of λ.
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Consider Fraunhoffer diffraction pattern obtained with a single slit i...
The phase difference between the wavelets from the opposite edges of the slit at the first diffraction minimum can be calculated using the formula for the phase difference in Fraunhofer diffraction:

Δφ = (2π/λ) * d * sin(θ)

where Δφ is the phase difference, λ is the wavelength of the incident light, d is the width of the slit, and θ is the angle of diffraction.

At the first diffraction minimum, the angle of diffraction θ is given by:

sin(θ) = λ / d

Substituting this into the formula for the phase difference, we get:

Δφ = (2π/λ) * d * (λ / d) = 2π

Therefore, the phase difference between the wavelets from the opposite edges of the slit at the first diffraction minimum is 2π radians.
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Consider Fraunhoffer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference (in radians) between the wavelets from the opposite edges of the slit isa)π / 4b)π / 2c)2 πd)πCorrect answer is option 'C'. Can you explain this answer?
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Consider Fraunhoffer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference (in radians) between the wavelets from the opposite edges of the slit isa)π / 4b)π / 2c)2 πd)πCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider Fraunhoffer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference (in radians) between the wavelets from the opposite edges of the slit isa)π / 4b)π / 2c)2 πd)πCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider Fraunhoffer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference (in radians) between the wavelets from the opposite edges of the slit isa)π / 4b)π / 2c)2 πd)πCorrect answer is option 'C'. Can you explain this answer?.
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