JEE Exam  >  JEE Questions  >  Two coaxial solenoids are made by winding thi... Start Learning for Free
Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is
0 = 4π × 10 –7 Tm A–1)
  • a)
    2.4π × 10–5 H
  • b)
    4.8π × 10–4 H
  • c)
    4.8π × 10–5 H
  • d)
    2.4π × 10–4 H
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Two coaxial solenoids are made by winding thin insulated wire over a p...
View all questions of this test
Most Upvoted Answer
Two coaxial solenoids are made by winding thin insulated wire over a p...
The mutual inductance between two coaxial solenoids can be calculated using the formula:

M = (μ₀ * N₁ * N₂ * A) / h

Where:
M = mutual inductance
μ₀ = permeability of free space (4π × 10^-7 Tm/A)
N₁, N₂ = number of turns in the two solenoids
A = cross-sectional area
h = length of the solenoids

Given:
N₁ = 300 turns
N₂ = 400 turns
A = 10 cm² = 10 × 10^-4 m²
h = 20 cm = 20 × 10^-2 m

Plugging in these values into the formula:

M = (4π × 10^-7 Tm/A) * (300 turns) * (400 turns) * (10 × 10^-4 m²) / (20 × 10^-2 m)

M = (4π × 10^-7 Tm/A) * (3 * 10^2) * (4 * 10^2) * (10 × 10^-4 m²) / (20 × 10^-2 m)

M = (4π × 10^-7 Tm/A) * (3 * 4) * (10^2 * 10^2) * (10 × 10^-4 m²) / (20 × 10^-2 m)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (20 × 10^-2 m)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (2)

Simplifying:

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (2)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (2)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (2)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (2)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (2)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (2)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²) / (2)

M = (4π × 10^-7 Tm/A) * (12) * (10^4) * (10 × 10^-4 m²)
Explore Courses for JEE exam
Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer?
Question Description
Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4π × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev