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A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. The
solenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutual
inductance will be –
solenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutual
inductance will be –
- a)μ0nN2πa2
- b)μ0nNπa2
- c)μ0n2Nπa2
- d)μ0n2N2πa2
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A circular coil of radius a and having N turns is placed at centre of ...
Flux due to solenoid of radius b at its centre in coil of radius a and divide by current u will got answr
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A circular coil of radius a and having N turns is placed at centre of ...
Yes, you are correct. In this configuration, the magnetic field inside the solenoid is uniform and parallel to its axis. The magnetic field due to the solenoid can be considered as a series of circular loops of current.
The magnetic field at a point inside the solenoid is given by:
B = μ₀nI
where μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.
Since the circular coil is placed at the center of the solenoid, the magnetic field due to the solenoid at the center of the coil will be perpendicular to the plane of the coil. This means that the magnetic field lines due to the solenoid will pass through the center of the coil.
The magnetic field due to the circular coil at its center is given by:
B = μ₀N/2a
where N is the number of turns in the coil and a is the radius of the coil.
Therefore, the total magnetic field at the center of the circular coil is the sum of the magnetic fields due to the solenoid and the circular coil:
B_total = B_solenoid + B_coil
= μ₀nI + μ₀N/2a
Thus, the magnetic field at the center of the circular coil is the sum of the magnetic fields due to the solenoid and the circular coil.
The magnetic field at a point inside the solenoid is given by:
B = μ₀nI
where μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.
Since the circular coil is placed at the center of the solenoid, the magnetic field due to the solenoid at the center of the coil will be perpendicular to the plane of the coil. This means that the magnetic field lines due to the solenoid will pass through the center of the coil.
The magnetic field due to the circular coil at its center is given by:
B = μ₀N/2a
where N is the number of turns in the coil and a is the radius of the coil.
Therefore, the total magnetic field at the center of the circular coil is the sum of the magnetic fields due to the solenoid and the circular coil:
B_total = B_solenoid + B_coil
= μ₀nI + μ₀N/2a
Thus, the magnetic field at the center of the circular coil is the sum of the magnetic fields due to the solenoid and the circular coil.
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A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. Thesolenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutualinductance will be –a)μ0nN2πa2b)μ0nNπa2c)μ0n2Nπa2d)μ0n2N2πa2Correct answer is option 'C'. Can you explain this answer?
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A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. Thesolenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutualinductance will be –a)μ0nN2πa2b)μ0nNπa2c)μ0n2Nπa2d)μ0n2N2πa2Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. Thesolenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutualinductance will be –a)μ0nN2πa2b)μ0nNπa2c)μ0n2Nπa2d)μ0n2N2πa2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. Thesolenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutualinductance will be –a)μ0nN2πa2b)μ0nNπa2c)μ0n2Nπa2d)μ0n2N2πa2Correct answer is option 'C'. Can you explain this answer?.
A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. Thesolenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutualinductance will be –a)μ0nN2πa2b)μ0nNπa2c)μ0n2Nπa2d)μ0n2N2πa2Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. Thesolenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutualinductance will be –a)μ0nN2πa2b)μ0nNπa2c)μ0n2Nπa2d)μ0n2N2πa2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. Thesolenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutualinductance will be –a)μ0nN2πa2b)μ0nNπa2c)μ0n2Nπa2d)μ0n2N2πa2Correct answer is option 'C'. Can you explain this answer?.
Solutions for A circular coil of radius a and having N turns is placed at centre of a long solenoid, coaxially. Thesolenoid has radius b (b >> a) and number of turns per unit length is n. Their coefficient of mutualinductance will be –a)μ0nN2πa2b)μ0nNπa2c)μ0n2Nπa2d)μ0n2N2πa2Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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