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Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is
0 = 4p × 10 –7 Tm A–1)
  • a)
    2.4π × 10–5 H
  • b)
    4.8π × 10–4 H
  • c)
    4.8π × 10–5 H
  • d)
    2.4π × 10–4 H
Correct answer is option 'D'. Can you explain this answer?
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The mutual inductance between two coaxial solenoids can be calculated using the formula:

M = μ₀ * N₁ * N₂ * A / L

where M is the mutual inductance, μ₀ is the permeability of free space (4π × 10^−7 T·m/A), N₁ and N₂ are the number of turns in the two solenoids, A is the cross-sectional area, and L is the length of the solenoids.

Given:
N₁ = 300 turns
N₂ = 400 turns
A = 10 cm² = 10 × 10^−4 m²
L = 20 cm = 20 × 10^−2 m

Plugging in these values into the formula:

M = (4π × 10^−7 T·m/A) * 300 * 400 * (10 × 10^−4 m²) / (20 × 10^−2 m)
M = (4π × 10^−7 T·m/A) * 300 * 400 * (10 × 10^−4 m²) / (0.2 m)
M = 12π × 10^−3 T·m * 300 * 400
M = 12π × 10^−3 T·m * 120000
M = 4.56π × 10^−1 T·m

Therefore, the mutual inductance between the two solenoids is approximately 0.456 T·m.
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Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4p × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer?
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Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4p × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4p × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A = 10 cm2 and length = 20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is(μ0 = 4p × 10 –7 Tm A–1)a)2.4π × 10–5 Hb)4.8π × 10–4 Hc)4.8π × 10–5 Hd)2.4π × 10–4 HCorrect answer is option 'D'. Can you explain this answer?.
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