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Total capacitance can be given as
- a)n(square Cg)
- b)nc(square Cg)
- c)c(square Cg)
- d)square Cg
Correct answer is option 'B'. Can you explain this answer?
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Total capacitance can be given asa)n(square Cg)b)nc(square Cg)c)c(squa...
Total capacitance can be given as the product of nc(square Cg) where c is the relative capacitance per section in terms of square Cg.
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Total capacitance can be given asa)n(square Cg)b)nc(square Cg)c)c(squa...
Calculation of Total Capacitance
Total capacitance in a circuit can be calculated by adding up the individual capacitances in parallel. If there are 'n' capacitors each with capacitance 'Cg', the total capacitance 'C_total' can be given as:
C_total = n * Cg
Therefore, the correct answer is option B which states 'nc(square Cg)'. This formula shows that the total capacitance is directly proportional to the number of capacitors in parallel and the individual capacitance of each capacitor.
Explanation of the Formula
- n: Number of capacitors connected in parallel
- Cg: Capacitance of each individual capacitor
- C_total: Total capacitance of the circuit
By multiplying the number of capacitors 'n' with the capacitance of each individual capacitor 'Cg', we get the total capacitance of the circuit. This formula is applicable when all the capacitors are connected in parallel, and their capacitances add up to give the overall capacitance.
Example
For instance, if we have 3 capacitors each with a capacitance of 10 μF connected in parallel, the total capacitance of the circuit would be:
C_total = 3 * 10 μF = 30 μF
This formula simplifies the calculation of total capacitance in circuits with multiple capacitors connected in parallel.
Total capacitance in a circuit can be calculated by adding up the individual capacitances in parallel. If there are 'n' capacitors each with capacitance 'Cg', the total capacitance 'C_total' can be given as:
C_total = n * Cg
Therefore, the correct answer is option B which states 'nc(square Cg)'. This formula shows that the total capacitance is directly proportional to the number of capacitors in parallel and the individual capacitance of each capacitor.
Explanation of the Formula
- n: Number of capacitors connected in parallel
- Cg: Capacitance of each individual capacitor
- C_total: Total capacitance of the circuit
By multiplying the number of capacitors 'n' with the capacitance of each individual capacitor 'Cg', we get the total capacitance of the circuit. This formula is applicable when all the capacitors are connected in parallel, and their capacitances add up to give the overall capacitance.
Example
For instance, if we have 3 capacitors each with a capacitance of 10 μF connected in parallel, the total capacitance of the circuit would be:
C_total = 3 * 10 μF = 30 μF
This formula simplifies the calculation of total capacitance in circuits with multiple capacitors connected in parallel.
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Total capacitance can be given asa)n(square Cg)b)nc(square Cg)c)c(square Cg)d)square CgCorrect answer is option 'B'. Can you explain this answer?
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