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The capacitors lose the charge over time due to
- a)The leakage resistance of the capacitor
- b)The small current in the transistor after being turned on
- c)The defect of the capacitor
- d)None of the mentioned
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The capacitors lose the charge over time due toa)The leakage resistanc...
Answer: a
Explanation: The capacitor loses charge due to the backward current of the transistro and due to the small resistance.
Explanation: The capacitor loses charge due to the backward current of the transistro and due to the small resistance.
Most Upvoted Answer
The capacitors lose the charge over time due toa)The leakage resistanc...
Leakage resistance of the capacitor:
The leakage resistance of the capacitor is the primary reason for the loss of charge over time. Capacitors are not perfect components and they have some internal resistance, known as leakage resistance. This resistance allows a small amount of current to flow through the capacitor even when it is fully charged. Over time, this leakage current causes the capacitor to discharge slowly.
Explanation:
When a capacitor is fully charged, the voltage across it should ideally remain constant. However, due to the leakage resistance, a small current flows through the capacitor, causing a gradual decrease in the voltage. This process is known as self-discharge and can be a significant factor in applications where the charge retention of the capacitor is crucial.
Impact:
The loss of charge due to the leakage resistance can affect the performance of circuits or devices that rely on capacitors to store energy or maintain voltage levels. In applications where capacitors are used for long-term energy storage or voltage regulation, the leakage current can lead to a decrease in the overall efficiency and reliability of the system.
Prevention:
To minimize the impact of leakage resistance, capacitors with low leakage values can be chosen for critical applications. Additionally, periodic recharging or replacement of capacitors may be necessary in situations where long-term charge retention is essential.
In conclusion, the leakage resistance of capacitors is a significant factor in the loss of charge over time. Understanding this phenomenon is crucial for designing reliable circuits and systems that depend on capacitor performance.
The leakage resistance of the capacitor is the primary reason for the loss of charge over time. Capacitors are not perfect components and they have some internal resistance, known as leakage resistance. This resistance allows a small amount of current to flow through the capacitor even when it is fully charged. Over time, this leakage current causes the capacitor to discharge slowly.
Explanation:
When a capacitor is fully charged, the voltage across it should ideally remain constant. However, due to the leakage resistance, a small current flows through the capacitor, causing a gradual decrease in the voltage. This process is known as self-discharge and can be a significant factor in applications where the charge retention of the capacitor is crucial.
Impact:
The loss of charge due to the leakage resistance can affect the performance of circuits or devices that rely on capacitors to store energy or maintain voltage levels. In applications where capacitors are used for long-term energy storage or voltage regulation, the leakage current can lead to a decrease in the overall efficiency and reliability of the system.
Prevention:
To minimize the impact of leakage resistance, capacitors with low leakage values can be chosen for critical applications. Additionally, periodic recharging or replacement of capacitors may be necessary in situations where long-term charge retention is essential.
In conclusion, the leakage resistance of capacitors is a significant factor in the loss of charge over time. Understanding this phenomenon is crucial for designing reliable circuits and systems that depend on capacitor performance.
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The capacitors lose the charge over time due toa)The leakage resistance of the capacitorb)The small current in the transistor after being turned onc)The defect of the capacitord)None of the mentionedCorrect answer is option 'A'. Can you explain this answer?
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