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Which of the following ions will exhibit colour in aqueous solutions? [2010]
  • a)
    La 3+ (Z = 57)
  • b)
    Ti3+ (Z = 22)
  • c)
    Lu 3+ (Z = 71)
  • d)
    Sc3+ (Z = 21)
Correct answer is option 'B'. Can you explain this answer?
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Which of the following ions will exhibit colour in aqueous solutions? ...
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Which of the following ions will exhibit colour in aqueous solutions? ...
Explanation:
In order to identify which ions will exhibit color in aqueous solutions, we need to consider the electronic configuration and the presence of unpaired electrons in the d-orbitals of the ion.

Electronic Configuration:
a) La3+ (Z = 57): The electronic configuration of La3+ is [Xe] 4f0 5d0 6s0. It does not have any d-orbitals to exhibit color.

b) Ti3+ (Z = 22): The electronic configuration of Ti3+ is [Ar] 3d1. It has one unpaired electron in the d-orbital, which can absorb light in the visible region and hence exhibit color.

c) Lu3+ (Z = 71): The electronic configuration of Lu3+ is [Xe] 4f14 5d0 6s0. It does not have any d-orbitals to exhibit color.

d) Sc3+ (Z = 21): The electronic configuration of Sc3+ is [Ar] 3d0. It does not have any unpaired electrons in the d-orbitals to exhibit color.

Presence of Unpaired Electrons:
In order for an ion to exhibit color, it must have unpaired electrons in the d-orbitals. This is because when a transition metal ion absorbs light in the visible region, an electron is promoted from a lower energy d-orbital to a higher energy d-orbital. The energy difference between these orbitals corresponds to a particular wavelength of light, which is absorbed and gives the ion its color.

Conclusion:
Among the given ions, only Ti3+ (Z = 22) has an unpaired electron in the d-orbital, allowing it to absorb light in the visible region and exhibit color. Therefore, the correct answer is option B.
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