Four successive members of the first row transition elements are liste...
For third ion ization enthalpy last configuration of
For third Ionization enthalpy Mn has stable configuration due to half filled d-orbital.
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Four successive members of the first row transition elements are liste...
Explanation:
The third ionization enthalpy refers to the energy required to remove the third electron from an atom. It is generally higher than the first and second ionization enthalpies because removing a third electron requires breaking into a filled inner shell.
To determine which element is expected to have the highest third ionization enthalpy among the given options, we need to consider their electronic configurations and atomic structures.
Electronic Configurations of the Given Elements:
a) Vanadium (Z = 23): [Ar] 3d3 4s2
b) Chromium (Z = 24): [Ar] 3d5 4s1
c) Manganese (Z = 25): [Ar] 3d5 4s2
d) Iron (Z = 26): [Ar] 3d6 4s2
Factors Affecting Ionization Enthalpy:
1. Effective Nuclear Charge: The greater the effective nuclear charge experienced by an electron, the more energy it will require to remove it.
2. Shielding Effect: The electron-electron repulsion reduces the effective nuclear charge experienced by outer electrons, making them easier to remove.
Factors Affecting Third Ionization Enthalpy:
1. Electron Configuration: The third ionization enthalpy involves removing an electron from a filled inner shell, which requires more energy due to increased electron-electron repulsion.
2. Effective Nuclear Charge: The effective nuclear charge experienced by the third electron will be influenced by the remaining electrons and the shielding effect.
Analysis:
Based on the given electronic configurations, we can observe the following:
1. Vanadium (Z = 23): The third electron is being removed from the 4s orbital, which is farther from the nucleus and experiences less effective nuclear charge.
2. Chromium (Z = 24): The third electron is being removed from the 4s orbital, similar to Vanadium.
3. Manganese (Z = 25): The third electron is being removed from the 3d orbital, which is closer to the nucleus and experiences a higher effective nuclear charge compared to the 4s orbital.
4. Iron (Z = 26): The third electron is being removed from the 3d orbital, similar to Manganese.
Conclusion:
Since Manganese (Z = 25) has the highest effective nuclear charge experienced by the third electron due to its electron configuration, it is expected to have the highest third ionization enthalpy among the given options. Therefore, option 'C' is the correct answer.