Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Since it uses the out of order mode of execut...
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Since it uses the out of order mode of execution, the results are stored in ______
- a)Buffers
- b)Special memory locations
- c)Temporary registers
- d)TLB
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Since it uses the out of order mode of execution, the results are stor...
Answer: c
Explanation: The results are stored in temporary locations and are arranged afterwards.
Explanation: The results are stored in temporary locations and are arranged afterwards.
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Since it uses the out of order mode of execution, the results are stor...
Temporary registers are used to store the results in out of order execution mode
1. Temporary registers:
In out of order execution mode, instructions are not necessarily executed in the order they appear in the program. This allows for better utilization of resources and improved performance.
Results of instructions are stored temporarily in special registers known as temporary registers. These registers hold the intermediate results until they can be committed to the main memory or other storage locations.
2. Role of temporary registers:
Temporary registers play a crucial role in the out of order execution process. They help in keeping track of the results of instructions as they are executed out of order.
These registers ensure that the correct dependencies between instructions are maintained and that the final results are ultimately stored in the appropriate memory locations.
3. Buffering:
While buffering is also an important concept in computer systems, in the context of out of order execution, temporary registers are specifically used to store the results.
Buffers, on the other hand, are used for temporarily holding data during data transfer between different components of a computer system.
Therefore, in the case of out of order execution mode, the results are stored in temporary registers to facilitate efficient execution of instructions and proper handling of dependencies between them.
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Since it uses the out of order mode of execution, the results are stored in ______a)Buffersb)Special memory locationsc)Temporary registersd)TLBCorrect answer is option 'C'. Can you explain this answer?
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