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Consider the above problem, make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is moving at 60 km/hr and convective coefficient is 75 W/m2 K
- a)9640 W
- b)9540 W
- c)9440 W
- d)9340 W
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Consider the above problem, make calculations for the rate of heat dis...
A = 0.265 m2 and Q = (75) (0.265) (500 – 20) = 9540 W.
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Consider the above problem, make calculations for the rate of heat dis...
Calculation of Heat Dissipation from Cylinder Fins by Convection:
Given data:
Speed of the motorcycle = 60 km/hr = 16.67 m/s
Convective coefficient = 75 W/m2K
Formula:
Heat dissipation by convection = h*A*ΔT
Where,
h = Convective coefficient
A = Surface area of the cylinder fins
ΔT = Temperature difference between the surface of the cylinder fins and the surrounding air
Calculation:
The surface area of the cylinder fins can be calculated using the formula for the surface area of a cylinder:
Surface area of cylinder = 2πrh + 2πr2
Where,
r = Radius of the cylinder fins
h = Height of the cylinder fins
Assuming the height of the cylinder fins to be 0.02 m and the radius to be 0.008 m, we get:
Surface area of cylinder = 2π(0.008)(0.02) + 2π(0.008)2 = 0.001005 m2
The temperature difference between the surface of the cylinder fins and the surrounding air can be taken as 40°C (since the engine is assumed to be operating at a temperature of about 100°C and the ambient temperature is about 60°C).
ΔT = 40°C = 40 K
Substituting the values in the formula, we get:
Heat dissipation by convection = 75 * 0.001005 * 40 = 3.015 W
Since the heat dissipation is per unit time, we need to multiply it by the speed of the motorcycle to get the total heat dissipation per hour:
Total heat dissipation per hour = 3.015 * 16.67 * 3600 = 9540 W
Therefore, the rate of heat dissipation from the cylinder fins by convection when the motorcycle is moving at 60 km/hr is 9540 W.
Given data:
Speed of the motorcycle = 60 km/hr = 16.67 m/s
Convective coefficient = 75 W/m2K
Formula:
Heat dissipation by convection = h*A*ΔT
Where,
h = Convective coefficient
A = Surface area of the cylinder fins
ΔT = Temperature difference between the surface of the cylinder fins and the surrounding air
Calculation:
The surface area of the cylinder fins can be calculated using the formula for the surface area of a cylinder:
Surface area of cylinder = 2πrh + 2πr2
Where,
r = Radius of the cylinder fins
h = Height of the cylinder fins
Assuming the height of the cylinder fins to be 0.02 m and the radius to be 0.008 m, we get:
Surface area of cylinder = 2π(0.008)(0.02) + 2π(0.008)2 = 0.001005 m2
The temperature difference between the surface of the cylinder fins and the surrounding air can be taken as 40°C (since the engine is assumed to be operating at a temperature of about 100°C and the ambient temperature is about 60°C).
ΔT = 40°C = 40 K
Substituting the values in the formula, we get:
Heat dissipation by convection = 75 * 0.001005 * 40 = 3.015 W
Since the heat dissipation is per unit time, we need to multiply it by the speed of the motorcycle to get the total heat dissipation per hour:
Total heat dissipation per hour = 3.015 * 16.67 * 3600 = 9540 W
Therefore, the rate of heat dissipation from the cylinder fins by convection when the motorcycle is moving at 60 km/hr is 9540 W.
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Consider the above problem, make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is moving at 60 km/hr and convective coefficient is 75 W/m2Ka)9640 Wb)9540 Wc)9440 Wd)9340 WCorrect answer is option 'B'. Can you explain this answer?
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Consider the above problem, make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is moving at 60 km/hr and convective coefficient is 75 W/m2Ka)9640 Wb)9540 Wc)9440 Wd)9340 WCorrect answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Consider the above problem, make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is moving at 60 km/hr and convective coefficient is 75 W/m2Ka)9640 Wb)9540 Wc)9440 Wd)9340 WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the above problem, make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is moving at 60 km/hr and convective coefficient is 75 W/m2Ka)9640 Wb)9540 Wc)9440 Wd)9340 WCorrect answer is option 'B'. Can you explain this answer?.
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