Chemistry Exam > Chemistry Questions > The de-Broglie wavelength of the electron in ...
Start Learning for Free
The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE = 13.6 eV, 1 eV = 1.6*10 -19J.
- a)33.29 nm
- b)3.329 nm
- c)0.3329 nm
- d)0.0332 nm
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The de-Broglie wavelength of the electron in the ground state of hydro...
De-Broglie wavelength of electron in hydrogen atom
Given:
KE = 13.6 eV
1 eV = 1.6 * 10^-19 J
Formula:
De-Broglie wavelength (λ) = h/p
where h = Planck's constant (6.626 * 10^-34 J s)
p = momentum of the electron
Calculation:
We know that KE = (1/2) mv^2
where m = mass of electron
v = velocity of electron
Rearranging this equation, we get:
v = √(2KE/m)
Substituting the given values, we get:
v = √(2 * 13.6 * 1.6 * 10^-19 / 9.1 * 10^-31) = 2.18 * 10^6 m/s
Now, we can calculate momentum of the electron:
p = mv = (9.1 * 10^-31) * (2.18 * 10^6) = 1.98 * 10^-24 kg m/s
Finally, we can calculate the De-Broglie wavelength:
λ = h/p = (6.626 * 10^-34) / (1.98 * 10^-24) = 3.329 nm
Therefore, the correct answer is option C (0.3329 nm).
Given:
KE = 13.6 eV
1 eV = 1.6 * 10^-19 J
Formula:
De-Broglie wavelength (λ) = h/p
where h = Planck's constant (6.626 * 10^-34 J s)
p = momentum of the electron
Calculation:
We know that KE = (1/2) mv^2
where m = mass of electron
v = velocity of electron
Rearranging this equation, we get:
v = √(2KE/m)
Substituting the given values, we get:
v = √(2 * 13.6 * 1.6 * 10^-19 / 9.1 * 10^-31) = 2.18 * 10^6 m/s
Now, we can calculate momentum of the electron:
p = mv = (9.1 * 10^-31) * (2.18 * 10^6) = 1.98 * 10^-24 kg m/s
Finally, we can calculate the De-Broglie wavelength:
λ = h/p = (6.626 * 10^-34) / (1.98 * 10^-24) = 3.329 nm
Therefore, the correct answer is option C (0.3329 nm).
Free Test
FREE
| Start Free Test |
Community Answer
The de-Broglie wavelength of the electron in the ground state of hydro...
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer?
Question Description
The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer?.
The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The de-Broglie wavelength of the electron in the ground state of hydrogen atom is ? Given: KE =13.6 eV, 1 eV = 1.6*10 -19J.a)33.29 nmb)3.329 nmc)0.3329 nmd)0.0332 nmCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup