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A piece of stone is thrown vertically upwards it reaches its Max Height in 3 seconds if the acceleration of the stone is 9.8 minutes / S² directed upwards calculate the initial velocity with which it is thrown upward find the Max Height attained by it?
Verified Answer
A piece of stone is thrown vertically upwards it reaches its Max Heigh...
At the max . height the final velocity of stone becomes 0 and t=3 and a=-9.8 because upward motion
v=u+a�t
put values
o=u-g*t
u=g*t
u=9.8*3=29.4m/s
This question is part of UPSC exam. View all Class 9 courses
Most Upvoted Answer
A piece of stone is thrown vertically upwards it reaches its Max Heigh...
Time = 3 second
acceleration = -9.8 m/s²
final velocity = 0 ( at higest point )
initial velocity = v - at
u = 0 - ( -9.8 x 3)
u = 0 - (-29.4)
u = 29.4 m/s
Max height ( distance )
s = ut + 1/2at²
s = 29.4 x 3 + (1/2 x -9.8 x 3 x 3 )
s = 88.2 + (-44.1
s = 88.2 - 44.1
s = 44.1 meter
Community Answer
A piece of stone is thrown vertically upwards it reaches its Max Heigh...
Given:
Acceleration of the stone (a) = 9.8 m/s² (upwards)
Time taken to reach max height (t) = 3 seconds

Calculating Initial Velocity:
To find the initial velocity with which the stone is thrown upward, we can use the following equation of motion:

v = u + at

where,
v = final velocity (which is 0 at max height)
u = initial velocity
a = acceleration (given)
t = time taken to reach max height (given)

Substituting the known values into the equation:

0 = u + (9.8)(3)
0 = u + 29.4

Solving for u:

u = -29.4 m/s

Therefore, the initial velocity with which the stone is thrown upward is -29.4 m/s. The negative sign indicates that the velocity is directed upward.

Calculating Max Height:
To calculate the maximum height attained by the stone, we can use the following equation of motion:

s = ut + (1/2)at²

where,
s = displacement (max height)
u = initial velocity (calculated as -29.4 m/s)
t = time taken to reach max height (given)
a = acceleration (given)

Substituting the known values into the equation:

s = (-29.4)(3) + (1/2)(9.8)(3)²
s = -88.2 + (1/2)(9.8)(9)
s = -88.2 + (4.9)(9)
s = -88.2 + 44.1
s = -44.1

Therefore, the maximum height attained by the stone is -44.1 meters. The negative sign indicates that the height is measured from the initial position downwards.

Explanation:
When the stone is thrown vertically upwards, it experiences an acceleration due to gravity directed downwards. However, in this problem, the acceleration is given as 9.8 m/s² directed upwards. This means that a force is acting on the stone in the opposite direction to gravity.

Using the equations of motion, we can calculate the initial velocity and the maximum height attained by the stone. The initial velocity is found by equating the final velocity (0 at max height) with the initial velocity and the time taken to reach max height. The negative sign indicates that the stone is thrown upwards.

The maximum height is calculated using the displacement equation, considering the initial velocity, time, and acceleration. The negative sign indicates that the height is measured downwards from the initial position.

In summary, the stone is thrown upwards with an initial velocity of -29.4 m/s and reaches a maximum height of -44.1 meters.
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A piece of stone is thrown vertically upwards it reaches its Max Height in 3 seconds if the acceleration of the stone is 9.8 minutes / S² directed upwards calculate the initial velocity with which it is thrown upward find the Max Height attained by it?
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