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The shear force obtained at the midpoint of the cantilever beam is 12 kN. What is the value of uniformly distributed load w (kN/m) acting over the entire length, if the span length of the beam is 4 m?
  • a)
    2
  • b)
    4
  • c)
    6
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The shear force obtained at the midpoint of the cantilever beam is 12 ...
Shear force at any section X-X is given by:

FX-X = wx
At x = 2m,
FX-X = 12kN
w × 2 = 12kN
w = 6 kN/m
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Most Upvoted Answer
The shear force obtained at the midpoint of the cantilever beam is 12 ...
Given Data:
- Shear force at the midpoint of the cantilever beam = 12 kN
- Span length of the beam = 4 m

Formula:
- The shear force (V) for a cantilever beam with a uniformly distributed load (w) can be calculated using the formula:
V = wL/2

Calculation:
- Given V = 12 kN and L = 4 m
- Using the formula V = wL/2, we can find the value of w:
12 = w * 4 / 2
12 = 2w
w = 12 / 2
w = 6 kN/m
Therefore, the value of uniformly distributed load (w) acting over the entire length of the cantilever beam is 6 kN/m. Hence, option 'C' is the correct answer.
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The shear force obtained at the midpoint of the cantilever beam is 12 kN. What is the value of uniformly distributed load w (kN/m) acting over the entire length, if the span length of the beam is 4 m?a)2b)4c)6d)8Correct answer is option 'C'. Can you explain this answer?
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