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Two steel rods connected by cotter joint are subjected to 50 kN load each. What is the minimum diameter required of the rods? (Given: Yielding Stress= 400N/mm² ; Factor of Safety=6)
  • a)
    31mm
  • b)
    35mm
  • c)
    36mm
  • d)
    40mm
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two steel rods connected by cotter joint are subjected to 50 kN load e...
Explanation: d=√(4P/πσ) where σ= Yielding Stress/F.S ; d=30.90mm or 31 mm.
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Most Upvoted Answer
Two steel rods connected by cotter joint are subjected to 50 kN load e...
To calculate the minimum diameter required for the rods, we need to consider the yield stress of the material and the load applied.

Given:
Yielding Stress = 400 N/mm^2
Load on each rod = 50 kN = 50,000 N

The formula to calculate the minimum diameter required is:

d = sqrt((4 * F) / (π * σ))

Where:
d = diameter of the rod
F = load on each rod
σ = yielding stress

Substituting the values:

d = sqrt((4 * 50,000) / (π * 400))

Calculating further:

d = sqrt(200,000 / (π * 400))
d = sqrt(500 / π)
d ≈ 12.65 mm

Therefore, the minimum diameter required for the rods is approximately 12.65 mm.
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