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If the low pass filter described by the difference equation y(n)=0.9y(n-1)+0.1x(n) is converted into a high pass filter, then what is the frequency response of the high pass filter?a)0.1/(1+0.9ejω)b)0.1/(1+0.9e-jω)c)0.1/(1-0.9ejω)d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about If the low pass filter described by the difference equation y(n)=0.9y(n-1)+0.1x(n) is converted into a high pass filter, then what is the frequency response of the high pass filter?a)0.1/(1+0.9ejω)b)0.1/(1+0.9e-jω)c)0.1/(1-0.9ejω)d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the low pass filter described by the difference equation y(n)=0.9y(n-1)+0.1x(n) is converted into a high pass filter, then what is the frequency response of the high pass filter?a)0.1/(1+0.9ejω)b)0.1/(1+0.9e-jω)c)0.1/(1-0.9ejω)d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer?.

Solutions for If the low pass filter described by the difference equation y(n)=0.9y(n-1)+0.1x(n) is converted into a high pass filter, then what is the frequency response of the high pass filter?a)0.1/(1+0.9ejω)b)0.1/(1+0.9e-jω)c)0.1/(1-0.9ejω)d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.

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