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A, B and C together can complete a piece of work in 10 days. All the three started working at it together and after 4 days, A left. Then, B and C together completed the work in 10 more days. A alone could complete the work in working
  • a)
    15 days
  • b)
    16 days
  • c)
    25 days
  • d)
    50 days
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A, B and C together can complete a piece of work in 10 days. All the t...
(A + B + C)'s one day work = 1 10
⇒ 4 day's work = 4 10 = 2 5 th
⇒ Remaining work = 3 5 th
B + C complete 3 5 th work in 10 days
= 50 3 days (i.e. 5 3 � 10)
Now,
1 10 - 3 50 = 1 25
Hence, A could complete the work alone in 25 days
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Most Upvoted Answer
A, B and C together can complete a piece of work in 10 days. All the t...
Given Data:
A, B, and C together can complete a piece of work in 10 days.
After 4 days, A left and B and C completed the work in 10 more days.
A alone could complete the work in x days.

Let's solve the problem step by step:

Step 1: Find the rate of work of A, B, and C together
Let the work be 1 unit.
A, B, and C together complete the work in 10 days, so their combined rate of work = 1/10 units per day.

Step 2: Find the work done by A, B, and C in 4 days
In 4 days, A, B, and C together would have completed 4*(1/10) = 2/5 of the work.

Step 3: Find the work remaining after 4 days
Since A left after 4 days, the remaining work = 1 - 2/5 = 3/5.

Step 4: Find the work done by B and C in 10 days
B and C together complete the remaining work in 10 days, so their combined rate of work = (3/5)/10 = 3/50 units per day.

Step 5: Find the work done by B and C in total
In 10 days, B and C together would have completed 10*(3/50) = 3/5 of the work.

Step 6: Find the work done by B and C after A left
Since A left after 4 days, the work done by B and C after A left = 3/5 - 2/5 = 1/5.

Step 7: Find the work done by B and C in 10 days after A left
Since B and C together complete the work in 10 more days after A left, the work done by B and C in 10 days = 1/5.

Step 8: Find the work done by B and C in 1 day after A left
Therefore, B and C's combined rate of work after A left = 1/10 units per day.

Step 9: Find the work done by B and C in total
In 10 days, B and C together would have completed 10*(1/10) = 1 unit of work.
Therefore, A alone could complete the work in 10 days.
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Locomotive engines are manufactured in a factory at Rampur. The process of manufacturing an engine involves 10 different activities - Activity 1 to Activity 10. Some of these 10 activities cannot be started until other activities have been completed. For example Activity 3 cannot begin until Activity 2 has been completed and Activity 4 cannot begin until both Activities 1 and 2 are completed. The table below shows the minimum time required to complete each activity and the list of activities which must be completed before a particular activity can be started. The manufacturing process of an engine is said to be finished if at least one of activities A9 and A10 is completed.Each activity can be undertaken by only one person at a time and one person can work on only one activity at a time.Q. What is the minimum possible number of days in which any individual can finish manufacturing an engine working alone, if both A9 and A10 are to be completed?

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A, B and C together can complete a piece of work in 10 days. All the three started working at it together and after 4 days, A left. Then, B and C together completed the work in 10 more days. A alone could complete the work in workinga) 15 days b) 16 days c) 25 days d) 50 days Correct answer is option 'C'. Can you explain this answer?
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