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A machine vice whose length of the handle is 150mm and the coefficient of friction for thread and collar are 0.15 and 0.17 respectively has a force applied at handle of 125N. Also the outer and inner diameters of collar are 55mm and 45mm respectively. Find the screw torque in terms of clamping force W if nominal diameter=22mm and pitch=5mm.
- a)3.567W N-mm
- b)2.286W N-mm
- c)3.564W N-mm
- d)None of the mentioned
Correct answer is option 'B'. Can you explain this answer?
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A machine vice whose length of the handle is 150mm and the coefficient...
Explanation: M₁=Wd x tan(Ǿ+ἀ)/2 or M₁=W x (22-0.5×2.5)x tan(4.66’+8.531’)/2 as tan(ἀ)=l/πd and tanǾ=0.15.
Most Upvoted Answer
A machine vice whose length of the handle is 150mm and the coefficient...
Screw torque can be calculated using the formula:
Torque = Force * Radius * Coefficient of friction
To calculate the radius (r), we need to find the mean diameter (d) of the collar, which can be calculated as:
Mean diameter (d) = (outer diameter + inner diameter) / 2
Given that the outer diameter (D) is 55mm and the inner diameter (d) is 45mm, we can substitute these values into the formula to find the mean diameter:
d = (55 + 45) / 2 = 50mm = 0.05m
The radius (r) is half the mean diameter, so:
r = d / 2 = 0.05 / 2 = 0.025m
Now we can calculate the screw torque:
Torque = Force * Radius * Coefficient of friction
Given that the force (F) is 125N and the coefficient of friction (μ) is 0.17, we can substitute these values into the formula:
Torque = 125 * 0.025 * 0.17
Simplifying the equation:
Torque = 2.125 N-m
Therefore, the screw torque in terms of the clamping force W is 2.125W N-m. However, none of the given options match this answer, so there may be an error in the options provided.
Torque = Force * Radius * Coefficient of friction
To calculate the radius (r), we need to find the mean diameter (d) of the collar, which can be calculated as:
Mean diameter (d) = (outer diameter + inner diameter) / 2
Given that the outer diameter (D) is 55mm and the inner diameter (d) is 45mm, we can substitute these values into the formula to find the mean diameter:
d = (55 + 45) / 2 = 50mm = 0.05m
The radius (r) is half the mean diameter, so:
r = d / 2 = 0.05 / 2 = 0.025m
Now we can calculate the screw torque:
Torque = Force * Radius * Coefficient of friction
Given that the force (F) is 125N and the coefficient of friction (μ) is 0.17, we can substitute these values into the formula:
Torque = 125 * 0.025 * 0.17
Simplifying the equation:
Torque = 2.125 N-m
Therefore, the screw torque in terms of the clamping force W is 2.125W N-m. However, none of the given options match this answer, so there may be an error in the options provided.
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A machine vice whose length of the handle is 150mm and the coefficient of friction for thread and collar are 0.15 and 0.17 respectively has a force applied at handle of 125N. Also the outer and inner diameters of collar are 55mm and 45mm respectively. Find the screw torque in terms of clamping force W if nominal diameter=22mm and pitch=5mm.a)3.567W N-mmb)2.286W N-mmc)3.564W N-mmd)None of the mentionedCorrect answer is option 'B'. Can you explain this answer?
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A machine vice whose length of the handle is 150mm and the coefficient of friction for thread and collar are 0.15 and 0.17 respectively has a force applied at handle of 125N. Also the outer and inner diameters of collar are 55mm and 45mm respectively. Find the screw torque in terms of clamping force W if nominal diameter=22mm and pitch=5mm.a)3.567W N-mmb)2.286W N-mmc)3.564W N-mmd)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A machine vice whose length of the handle is 150mm and the coefficient of friction for thread and collar are 0.15 and 0.17 respectively has a force applied at handle of 125N. Also the outer and inner diameters of collar are 55mm and 45mm respectively. Find the screw torque in terms of clamping force W if nominal diameter=22mm and pitch=5mm.a)3.567W N-mmb)2.286W N-mmc)3.564W N-mmd)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A machine vice whose length of the handle is 150mm and the coefficient of friction for thread and collar are 0.15 and 0.17 respectively has a force applied at handle of 125N. Also the outer and inner diameters of collar are 55mm and 45mm respectively. Find the screw torque in terms of clamping force W if nominal diameter=22mm and pitch=5mm.a)3.567W N-mmb)2.286W N-mmc)3.564W N-mmd)None of the mentionedCorrect answer is option 'B'. Can you explain this answer?.
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