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A capacitor of 50 pF is connected to an AC source of frequency 1kHz. Calculate its reactance ?
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A capacitor of 50 pF is connected to an AC source of frequency 1kHz. C...
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Reactance of a Capacitor

Introduction:
Reactance is a measure of the opposition offered by a component to the flow of alternating current (AC). In the case of a capacitor, its reactance is inversely proportional to the frequency of the AC source.

Formula:
The reactance (Xc) of a capacitor can be calculated using the formula:
Xc = 1 / (2 * π * f * C)

Where:
Xc = Reactance of the capacitor
π = Pi (approximately 3.14159)
f = Frequency of the AC source
C = Capacitance of the capacitor

Given:
Capacitance (C) = 50 pF = 50 × 10^(-12) F
Frequency (f) = 1 kHz = 1 × 10^3 Hz

Calculations:
Using the given values in the formula, we can calculate the reactance of the capacitor as follows:

Xc = 1 / (2 * π * f * C)
= 1 / (2 * 3.14159 * 1 × 10^3 * 50 × 10^(-12))
≈ 1 / (314.159 * 5 × 10^(-11))
≈ 6.37 × 10^6 Ω

Therefore, the reactance of the capacitor is approximately 6.37 megaohms (Ω).

Explanation:
The reactance of a capacitor is determined by its capacitance and the frequency of the AC source. In this case, the given capacitor has a capacitance of 50 pF (picofarads) and is connected to an AC source with a frequency of 1 kHz (kilohertz).

Using the formula for reactance, we substitute the given values and calculate the reactance of the capacitor. The reactance is found to be approximately 6.37 megaohms (Ω).

Summary:
The reactance of a capacitor is inversely proportional to the frequency of the AC source. In this case, the reactance of a 50 pF capacitor connected to a 1 kHz AC source is approximately 6.37 megaohms (Ω).
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Read the following text and answer the following questions on the basis of the same: Tuning a radio set: In essence the simplest tuned radio frequency receiver is a simple crystal set. Desired frequency is tuned by a tuned coil / capacitor combination, and then the signal is presented to a simple crystal or diode detector where the amplitude modulated signal, is demodulated. This is then passed straight to the headphones or speaker. In radio set there is an LC oscillator comprising of a variable capacitor (or sometimes a variable coupling coil), with a knob on the front panel to tune the receiver. Capacitor used in old radio sets is gang capacitor. It consists of two sets of parallel circular plates one of which can rotate manually by means of a knob. The rotation causes overlapping areas of plates to change, thus changing its capacitance. Air gap between plates acts as dielectric. The capacitor has to be tuned in tandem corresponding to the frequency of a station so that the LC combination of the radio set resonates at the frequency of the desired station.When capacitive reactance (XC) is equal to the inductive reactance (XL), then the resonance occurs and the resonant frequency is given by ω0 = 1/√LCcurrent amplitude becomes maximum at the resonant frequency. It is important to note that resonance phenomenon is exhibited by a circuit only if both L and C are present in the circuit. Only then do the voltages across L and C cancel each other (both being out of phas e) and the Current amplitude is Vm/R the total source voltage appearing across R. This means that we cannot have resonance in a RL or RC circuit.Capacitor used in radio set for tuning is a

A capacitor of 50 pF is connected to an AC source of frequency 1kHz. Calculate its reactance ?
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