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A solution of sucrose (molar mass = 342 g mol–1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be ( f for water = 1.86 K kg mol–1). [2010]a)– 0.372°Cb)– 0.520°Cc)+ 0.372°Cd)– 0.570°CCorrect answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A solution of sucrose (molar mass = 342 g mol–1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be ( f for water = 1.86 K kg mol–1). [2010]a)– 0.372°Cb)– 0.520°Cc)+ 0.372°Cd)– 0.570°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of sucrose (molar mass = 342 g mol–1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be ( f for water = 1.86 K kg mol–1). [2010]a)– 0.372°Cb)– 0.520°Cc)+ 0.372°Cd)– 0.570°CCorrect answer is option 'A'. Can you explain this answer?.

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