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When a certain conductivity cell was filled with 0.01 M solution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is
- a)0.00180
- b)0.00170
- c)0.00130
- d)0.00120
Correct answer is option 'C'. Can you explain this answer?
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When a certain conductivity cell was filled with 0.01 Msolution of KCl...
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When a certain conductivity cell was filled with 0.01 Msolution of KCl...
Actually, specific conductance is reciprocal of specific resistance so it's given 700 so
specific conductance=1/700
=option c
specific conductance=1/700
=option c
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When a certain conductivity cell was filled with 0.01 Msolution of KCl...
The specific resistance (ρ) is given by the formula:
ρ = R × A / L
Where:
- ρ is the specific resistance in ohm cm
- R is the resistance in ohms
- A is the cross-sectional area of the cell in cm²
- L is the length of the cell in cm
First, we need to calculate the specific resistance of the KCl solution:
ρ(KCl) = 700 ohm cm
The resistance of the KCl solution is given as 160 ohms. Let's assume the cross-sectional area and length of the cell are constant for both solutions.
ρ(KCl) = R(KCl) × A / L
Solving for A / L:
A / L = ρ(KCl) / R(KCl)
= 700 ohm cm / 160 ohms
= 4.375 cm
Now, let's calculate the specific conductance of the NaOH solution using the resistance given as 190 ohms:
ρ(NaOH) = R(NaOH) × A / L
Solving for ρ(NaOH):
ρ(NaOH) = R(NaOH) × A / L
= 190 ohms × (4.375 cm)
= 831.25 ohm cm
Therefore, the specific conductance of the NaOH solution is 831.25 ohm cm.
ρ = R × A / L
Where:
- ρ is the specific resistance in ohm cm
- R is the resistance in ohms
- A is the cross-sectional area of the cell in cm²
- L is the length of the cell in cm
First, we need to calculate the specific resistance of the KCl solution:
ρ(KCl) = 700 ohm cm
The resistance of the KCl solution is given as 160 ohms. Let's assume the cross-sectional area and length of the cell are constant for both solutions.
ρ(KCl) = R(KCl) × A / L
Solving for A / L:
A / L = ρ(KCl) / R(KCl)
= 700 ohm cm / 160 ohms
= 4.375 cm
Now, let's calculate the specific conductance of the NaOH solution using the resistance given as 190 ohms:
ρ(NaOH) = R(NaOH) × A / L
Solving for ρ(NaOH):
ρ(NaOH) = R(NaOH) × A / L
= 190 ohms × (4.375 cm)
= 831.25 ohm cm
Therefore, the specific conductance of the NaOH solution is 831.25 ohm cm.
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When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer?
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When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer?.
When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer?.
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When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer?, a detailed solution for When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of When a certain conductivity cell was filled with 0.01 Msolution of KCl, it had a resistance of 160 ohm at 250C and when filled with 0.005 M NaOH, it had a resistance of 190 ohm. If specific resistance of KCl solution is 700 ohm cm, specific conductance (ohm—1 cm—1) of NaOH solution is a)0.00180 b)0.00170 c)0.00130 d)0.00120Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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