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A single-phase voltage controller, using one SCR in anti parallel with a diode, feeds a load R and Vs = 230 V. For a firing angel of 90° for the SCR, the PMMC voltage connected across R would read
- a)0
- b)51.8 V
- c)–51.8 V
- d)–36.82 V
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A single-phase voltage controller, using one SCR in anti parallel with...
As firing angle is 90, there is ideally be no conduction in the positive half. Hence, the average value will be zero.
Vo = (√2 Vs)/2π x (cos90 – 1) = – 51.8 V.
Vo = (√2 Vs)/2π x (cos90 – 1) = – 51.8 V.
Most Upvoted Answer
A single-phase voltage controller, using one SCR in anti parallel with...
The given information states that a single-phase voltage controller is being used, which means that it controls the output voltage to the load by controlling the conduction angle of the SCR (Silicon Controlled Rectifier).
In this case, the SCR is connected in anti-parallel with a diode. The anti-parallel diode is used to ensure that the current can flow in both directions, allowing for the control of both positive and negative halves of the AC waveform.
The load is denoted as R, and the supply voltage is Vs = 230 V.
Now, for a firing angle of 90 degrees, it means that the SCR starts conducting at 90 degrees into the positive half-cycle of the AC waveform. This means that the SCR is turned on when the voltage across it reaches a certain threshold value.
Since the SCR is connected in anti-parallel with a diode, it conducts when the AC waveform is positive and the diode conducts when the AC waveform is negative.
Therefore, when the SCR starts conducting at 90 degrees, it allows the positive half of the AC waveform to flow through the load R.
The output voltage can be calculated using the formula:
Vout = Vs * (1 - cos(α))
Where α is the firing angle in radians.
For a firing angle of 90 degrees, α = π/2 radians.
Plugging in the values:
Vout = 230 * (1 - cos(π/2))
Vout = 230 * (1 - 0)
Vout = 230 V
So, when the firing angle is 90 degrees, the output voltage is 230 V.
In this case, the SCR is connected in anti-parallel with a diode. The anti-parallel diode is used to ensure that the current can flow in both directions, allowing for the control of both positive and negative halves of the AC waveform.
The load is denoted as R, and the supply voltage is Vs = 230 V.
Now, for a firing angle of 90 degrees, it means that the SCR starts conducting at 90 degrees into the positive half-cycle of the AC waveform. This means that the SCR is turned on when the voltage across it reaches a certain threshold value.
Since the SCR is connected in anti-parallel with a diode, it conducts when the AC waveform is positive and the diode conducts when the AC waveform is negative.
Therefore, when the SCR starts conducting at 90 degrees, it allows the positive half of the AC waveform to flow through the load R.
The output voltage can be calculated using the formula:
Vout = Vs * (1 - cos(α))
Where α is the firing angle in radians.
For a firing angle of 90 degrees, α = π/2 radians.
Plugging in the values:
Vout = 230 * (1 - cos(π/2))
Vout = 230 * (1 - 0)
Vout = 230 V
So, when the firing angle is 90 degrees, the output voltage is 230 V.
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A single-phase voltage controller, using one SCR in anti parallel with a diode, feeds a load R and Vs = 230 V. For a firing angel of 90° for the SCR, the PMMC voltage connected across R would reada)0b)51.8 Vc)–51.8 Vd)–36.82 VCorrect answer is option 'C'. Can you explain this answer?
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A single-phase voltage controller, using one SCR in anti parallel with a diode, feeds a load R and Vs = 230 V. For a firing angel of 90° for the SCR, the PMMC voltage connected across R would reada)0b)51.8 Vc)–51.8 Vd)–36.82 VCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single-phase voltage controller, using one SCR in anti parallel with a diode, feeds a load R and Vs = 230 V. For a firing angel of 90° for the SCR, the PMMC voltage connected across R would reada)0b)51.8 Vc)–51.8 Vd)–36.82 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single-phase voltage controller, using one SCR in anti parallel with a diode, feeds a load R and Vs = 230 V. For a firing angel of 90° for the SCR, the PMMC voltage connected across R would reada)0b)51.8 Vc)–51.8 Vd)–36.82 VCorrect answer is option 'C'. Can you explain this answer?.
A single-phase voltage controller, using one SCR in anti parallel with a diode, feeds a load R and Vs = 230 V. For a firing angel of 90° for the SCR, the PMMC voltage connected across R would reada)0b)51.8 Vc)–51.8 Vd)–36.82 VCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single-phase voltage controller, using one SCR in anti parallel with a diode, feeds a load R and Vs = 230 V. For a firing angel of 90° for the SCR, the PMMC voltage connected across R would reada)0b)51.8 Vc)–51.8 Vd)–36.82 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single-phase voltage controller, using one SCR in anti parallel with a diode, feeds a load R and Vs = 230 V. For a firing angel of 90° for the SCR, the PMMC voltage connected across R would reada)0b)51.8 Vc)–51.8 Vd)–36.82 VCorrect answer is option 'C'. Can you explain this answer?.
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