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Factorise : 8a3 + b3 + 12a2 b + 6ab2
- a)(2a + b) (2a + b) (2a + b)
- b)(2a – b) (2a – b) (2a + b)
- c)(a+b)(2a+2b)(a+2b)
- d)(-2a + b) (-2a + b) (2a + b)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a &nd...
8a3 + b3+ 12a2b + 6ab2
8a3 + b3+ 12a2b + 6ab2
= (2a)3 + (b)3 + 3(2a)(b) (2a + b)
= (2a + b)3 | Using Identity VI
= (2a + b)(2a + b)(2a + b)
8a3 + b3+ 12a2b + 6ab2
= (2a)3 + (b)3 + 3(2a)(b) (2a + b)
= (2a + b)3 | Using Identity VI
= (2a + b)(2a + b)(2a + b)
Most Upvoted Answer
Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a &nd...
The given expression is:
8a^3 b^3 + 12a^2b + 6ab^2
To factorize this expression, we can look for common factors in each term.
Taking out the common factor of 2ab from each term, we get:
2ab(4a^2b^2 + 6a + 3b)
Now, let's factorize the remaining expression inside the parentheses:
The expression 4a^2b^2 + 6a + 3b cannot be factored further as it does not have any common factors or a simple pattern.
Therefore, the fully factorized form of the given expression is:
2ab(4a^2b^2 + 6a + 3b)
8a^3 b^3 + 12a^2b + 6ab^2
To factorize this expression, we can look for common factors in each term.
Taking out the common factor of 2ab from each term, we get:
2ab(4a^2b^2 + 6a + 3b)
Now, let's factorize the remaining expression inside the parentheses:
The expression 4a^2b^2 + 6a + 3b cannot be factored further as it does not have any common factors or a simple pattern.
Therefore, the fully factorized form of the given expression is:
2ab(4a^2b^2 + 6a + 3b)
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Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer?
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Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer?.
Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer?.
Solutions for Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 9.
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Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Factorise : 8a3+ b3+ 12a2b + 6ab2a)(2a + b) (2a + b) (2a + b)b)(2a – b) (2a – b) (2a + b)c)(a+b)(2a+2b)(a+2b)d)(-2a + b) (-2a + b) (2a + b)Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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