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A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?
- a)533 N
- b)666 N
- c)133 N
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a c...
Maximum Secondary force Maximum shaking force
= mw2r {cosq + (cos 2q / n)}
[n = (l/r) = (200/50) = 4]
= 1.2 {(2p x 900) / 60}2 x 50 x 10-3 (1+(1/4))
(at q = 0°)
f = 666 N.
= mw2r {cosq + (cos 2q / n)}
[n = (l/r) = (200/50) = 4]
= 1.2 {(2p x 900) / 60}2 x 50 x 10-3 (1+(1/4))
(at q = 0°)
f = 666 N.
Most Upvoted Answer
A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a c...
Force acting on the piston during one cycle of operation?
We can use the equation for maximum force on the piston:
F = (m_reciprocating * L) * (ω^2 * r^2 - 1)
where:
- F is the maximum force on the piston
- m_reciprocating is the effective reciprocating mass of the engine
- L is the length of the connecting rod
- ω is the angular velocity of the engine (in radians per second)
- r is the ratio of the crank length to the connecting rod length (r = L/R)
First, we need to convert the engine's rotational speed from rpm to radians per second:
ω = (2π/60) * 900 = 94.25 rad/s
Next, we can calculate the ratio of the crank length to the connecting rod length:
r = 50/200 = 0.25
Now we can plug in the values and solve for F:
F = (1.2 * 0.2) * (94.25^2 * 0.25^2 - 1)
F ≈ 626 N
Therefore, the approximate magnitude of the maximum force acting on the piston during one cycle of operation is 626 N.
We can use the equation for maximum force on the piston:
F = (m_reciprocating * L) * (ω^2 * r^2 - 1)
where:
- F is the maximum force on the piston
- m_reciprocating is the effective reciprocating mass of the engine
- L is the length of the connecting rod
- ω is the angular velocity of the engine (in radians per second)
- r is the ratio of the crank length to the connecting rod length (r = L/R)
First, we need to convert the engine's rotational speed from rpm to radians per second:
ω = (2π/60) * 900 = 94.25 rad/s
Next, we can calculate the ratio of the crank length to the connecting rod length:
r = 50/200 = 0.25
Now we can plug in the values and solve for F:
F = (1.2 * 0.2) * (94.25^2 * 0.25^2 - 1)
F ≈ 626 N
Therefore, the approximate magnitude of the maximum force acting on the piston during one cycle of operation is 626 N.
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A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?a)533 Nb)666 Nc)133 Nd)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?a)533 Nb)666 Nc)133 Nd)None of the aboveCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?a)533 Nb)666 Nc)133 Nd)None of the aboveCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?a)533 Nb)666 Nc)133 Nd)None of the aboveCorrect answer is option 'B'. Can you explain this answer?.
A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?a)533 Nb)666 Nc)133 Nd)None of the aboveCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?a)533 Nb)666 Nc)133 Nd)None of the aboveCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?a)533 Nb)666 Nc)133 Nd)None of the aboveCorrect answer is option 'B'. Can you explain this answer?.
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