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A single slider vertical engine shiwn in figure has a bore of 30.5 cm and a 80cm long connecting rod with a stroke of 40 cm. the nass of reciprocating part is 135 kg . when the pistion is at quater stroke and is moving downwards, the net pressure on it is 650 kN/m2 . if the speed of the engine is 250 rpm .the turning moment on the crank shaft ar the instant corresponding to the piston shown in figure will be?
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A single slider vertical engine shiwn in figure has a bore of 30.5 cm ...
Problem Statement

A single slider vertical engine has a bore of 30.5 cm and a 80 cm long connecting rod with a stroke of 40 cm. The mass of reciprocating part is 135 kg. When the piston is at quarter stroke and is moving downwards, the net pressure on it is 650 kN/m2. If the speed of the engine is 250 rpm, the turning moment on the crankshaft at the instant corresponding to the piston shown in the figure will be?


Solution

Given:


  • Bore = 30.5 cm

  • Connecting rod length = 80 cm

  • Stroke = 40 cm

  • Mass of reciprocating part = 135 kg

  • Net pressure on piston = 650 kN/m2

  • Engine speed = 250 rpm



Step 1: Calculate the piston area

The area of the piston can be calculated using the formula:

Area of piston = π/4 x (bore)2

Substituting the given values, we get:

Area of piston = π/4 x (0.305)2 = 0.0735 m2


Step 2: Calculate the force acting on the piston

The force acting on the piston can be calculated using the formula:

Force on piston = Net pressure x Area of piston

Substituting the given values, we get:

Force on piston = 650 x 103 x 0.0735 = 47.775 kN


Step 3: Calculate the velocity of the piston

The velocity of the piston can be calculated using the formula:

Velocity of piston = (2 x Stroke x Engine speed)/60

Substituting the given values, we get:

Velocity of piston = (2 x 0.4 x 250)/60 = 3.333 m/s


Step 4: Calculate the acceleration of the piston

The acceleration of the piston can be calculated using the formula:

Acceleration of piston = (2 x Stroke x Engine speed2)/60 x connecting rod length

Substituting the given values, we get:

Acceleration of piston = (2 x 0.4 x (250)2)/60 x 0.8 = 109.72 m/s2


Step 5: Calculate the inertia force of the reciprocating parts

The inertia force of the reciprocating parts can be calculated using the formula:

Inertia force = Mass of reciprocating parts x Acceleration of piston

Substituting the given values, we get:

Inertia force = 135 x 109.72 = 14827.2 N


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A single slider vertical engine shiwn in figure has a bore of 30.5 cm and a 80cm long connecting rod with a stroke of 40 cm. the nass of reciprocating part is 135 kg . when the pistion is at quater stroke and is moving downwards, the net pressure on it is 650 kN/m2 . if the speed of the engine is 250 rpm .the turning moment on the crank shaft ar the instant corresponding to the piston shown in figure will be?
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A single slider vertical engine shiwn in figure has a bore of 30.5 cm and a 80cm long connecting rod with a stroke of 40 cm. the nass of reciprocating part is 135 kg . when the pistion is at quater stroke and is moving downwards, the net pressure on it is 650 kN/m2 . if the speed of the engine is 250 rpm .the turning moment on the crank shaft ar the instant corresponding to the piston shown in figure will be? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A single slider vertical engine shiwn in figure has a bore of 30.5 cm and a 80cm long connecting rod with a stroke of 40 cm. the nass of reciprocating part is 135 kg . when the pistion is at quater stroke and is moving downwards, the net pressure on it is 650 kN/m2 . if the speed of the engine is 250 rpm .the turning moment on the crank shaft ar the instant corresponding to the piston shown in figure will be? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single slider vertical engine shiwn in figure has a bore of 30.5 cm and a 80cm long connecting rod with a stroke of 40 cm. the nass of reciprocating part is 135 kg . when the pistion is at quater stroke and is moving downwards, the net pressure on it is 650 kN/m2 . if the speed of the engine is 250 rpm .the turning moment on the crank shaft ar the instant corresponding to the piston shown in figure will be?.
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