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An RL series AC circuit has R = 10 ohm and X= 10 ohms. It is connected to an AC voltage source, the phase angle between voltage and current is
  • a)
    30°
  • b)
    45°
  • c)
    60°
  • d)
    36.8°
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
An RL series AC circuit has R = 10 ohm and XL= 10 ohms. It is connecte...
R = 10 ohm and X= 10 ohm
Impedance of RL circuit is, 

Power factor cos 
⇒ Phase difference (ϕ) = 45°
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Most Upvoted Answer
An RL series AC circuit has R = 10 ohm and XL= 10 ohms. It is connecte...
The phase angle between voltage and current in an RL series AC circuit can be calculated using the formula:

tan(θ) = XL / R

Given that R = 10 ohm and XL = 10 ohm, we can substitute these values into the formula:

tan(θ) = 10 / 10
tan(θ) = 1

To find the angle θ, we can take the inverse tangent (arctan) of both sides:

θ = arctan(1)

Using a calculator, we find that arctan(1) is equal to approximately 45 degrees.

Therefore, the phase angle between voltage and current in this RL series AC circuit is approximately 45 degrees.
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An RL series AC circuit has R = 10 ohm and XL= 10 ohms. It is connected to an AC voltage source, the phase angle between voltage and current isa)30°b)45°c)60°d)36.8°Correct answer is option 'B'. Can you explain this answer?
Question Description
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