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A simply supported beam is of rectangular section. It carries a uniformly distributed load over the whole span. The deflection at the centre is “y”. If the depth of the beam is doubled, the deflection at centre will be:
  • a)
    2 y
  • b)
    4 y
  • c)
    y/8 
  • d)
    y/2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A simply supported beam is of rectangular section. It carries a unifor...
Deflection of beam is inversely proportional to area moment of inertia of the beam.
Moment of inertia for rectangular section,  
Let the final deflection is yfinal when the depth is doubled.
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Most Upvoted Answer
A simply supported beam is of rectangular section. It carries a unifor...
The deflection at the center of a simply supported beam of rectangular section can be calculated using the formula for deflection in beams:

δ = (5 * w * L^4) / (384 * E * I)

Where:
δ = deflection at the center
w = uniformly distributed load
L = span of the beam
E = modulus of elasticity of the material
I = moment of inertia of the beam section

In the case of a rectangular section beam, the moment of inertia can be calculated using the formula:

I = (b * h^3) / 12

Where:
b = width of the beam
h = height of the beam

By substituting the given values into the formulas, the deflection at the center of the beam can be calculated.
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A simply supported beam is of rectangular section. It carries a uniformly distributed load over the whole span. The deflection at the centre is “y”. If the depth of the beam is doubled, the deflection at centre will be:a)2 yb)4 yc)y/8d)y/2Correct answer is option 'C'. Can you explain this answer?
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