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The initial velocity of a body moving along a straight line is 7 m/s. It has a uniform acceleration of 4 m/s�. The distance covered by the body in the 5th second of its motion is
- a)25 m
- b)35 m
- c)50 m
- d)85 m
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The initial velocity of a body moving along a straight line is 7 m/s. ...
Given, u = 7m/s
a = 4m/s2
n = 5
The distance covered by the body in nth sec is given by
Sn = u + a/2(2n−1)
S5 = 7 + 24(2×5−1)
S5 = 25 m
Most Upvoted Answer
The initial velocity of a body moving along a straight line is 7 m/s. ...
Given, u = 7m/s
a = 4m/s2
n = 5
The distance covered by the body in nth sec is given by
Sn = u + a/2(2n−1)
S5 = 7 + 24(2×5−1)
S5 = 25 m
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Community Answer
The initial velocity of a body moving along a straight line is 7 m/s. ...
Given data:
Initial velocity (u) = 7 m/s
Acceleration (a) = 4 m/s^2
Distance covered in the 5th second:
To find the distance covered by the body in the 5th second of its motion, we need to first calculate the final velocity at the end of the 4th second and then use it to find the distance covered in the 5th second.
Calculating final velocity at the end of the 4th second:
Using the equation of motion: v = u + at
Here, u = 7 m/s, a = 4 m/s^2, and t = 4 seconds
v = 7 + 4*4
v = 7 + 16
v = 23 m/s
Distance covered in the 5th second:
Now, in the 5th second, the body starts with a velocity of 23 m/s. We can calculate the distance covered using the equation of motion: s = ut + (1/2)at^2
Here, u = 23 m/s, a = 4 m/s^2, and t = 1 second
s = 23*1 + (1/2)*4*1^2
s = 23 + 2
s = 25 m
Therefore, the distance covered by the body in the 5th second of its motion is 25 meters. So, option 'A' (25 m) is the correct answer.
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The initial velocity of a body moving along a straight line is 7 m/s. It has a uniform acceleration of 4 m/s�. The distance covered by the body in the 5th second of its motion isa)25 mb)35 mc)50 md)85 mCorrect answer is option 'A'. Can you explain this answer?
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