The average force necessary to stop a hammer with momentum p Nsin 0.5s can be determined by using the formula for average force:

Average Force = Change in Momentum / Time

In this case, the momentum of the hammer is given as p Nsin 0.5s. To calculate the change in momentum, we need to know the initial momentum and the final momentum.

Initial momentum: The initial momentum is assumed to be zero since the hammer is at rest before it is stopped.

Final momentum: The final momentum is given as p Nsin 0.5s.

Change in momentum = Final momentum - Initial momentum = p Nsin 0.5s - 0 = p Nsin 0.5s

Therefore, the change in momentum is equal to p Nsin 0.5s.

Now, we need to determine the time it takes to stop the hammer. The time is given as 0.5s.

Average Force = p Nsin 0.5s / 0.5s

Simplifying the expression, we find that the average force required to stop the hammer is equal to p Nsin 0.5s / 0.5s.

Explanation of the Formula:

- Average Force: The average force is the force exerted over a given period of time. It represents the rate of change of momentum.
- Change in Momentum: The change in momentum is the difference between the final momentum and the initial momentum of an object.
- Time: The time is the duration over which the force is applied.

Key Points:

- Average Force = Change in Momentum / Time
- The initial momentum is assumed to be zero since the hammer is at rest before it is stopped.
- The final momentum is given as p Nsin 0.5s.
- The change in momentum is equal to p Nsin 0.5s.
- The time taken to stop the hammer is 0.5s.
- Therefore, the average force required to stop the hammer is equal to p Nsin 0.5s / 0.5s.