A body of mass 5 kg is moving with a velocity of v =(2i 6j)m/s at t=0 ...
Given information:
- Mass of the body, m = 5 kg
- Initial velocity, v₀ = 2i + 6j m/s at t = 0 s
- Final velocity, v = 10i + 6j m/s at t = 2 s
Calculating change in velocity:
The change in velocity can be calculated by subtracting the initial velocity from the final velocity.
Δv = v - v₀
Δv = (10i + 6j) - (2i + 6j)
Δv = 8i + 0j
Calculating change in momentum:
The change in momentum can be calculated using the equation:
Δp = m * Δv
Δp = 5 kg * (8i + 0j)
Δp = 40i + 0j
Explaining the change in momentum:
- Momentum is a vector quantity that depends on the mass and velocity of an object.
- It is given by the equation: p = m * v, where p is momentum, m is mass, and v is velocity.
- The change in momentum, Δp, is the difference between the final momentum and the initial momentum of an object.
- In this case, we are given the initial velocity and final velocity of a body.
- To calculate the change in momentum, we first find the change in velocity by subtracting the initial velocity from the final velocity.
- The change in velocity is found to be 8i + 0j m/s.
- We then multiply the change in velocity by the mass of the body to find the change in momentum.
- The change in momentum is found to be 40i + 0j kg·m/s.
- Since momentum is a vector quantity, it has both magnitude and direction.
- The change in momentum tells us how the momentum of the body has changed over time.
- In this case, the change in momentum is in the x-direction, with a magnitude of 40 kg·m/s.
- This means that the body has gained momentum in the positive x-direction over the given time interval.
A body of mass 5 kg is moving with a velocity of v =(2i 6j)m/s at t=0 ...
40
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